According to the kinetic-molecular theory, gases condense into liquids because of

Picture attached please help! 2 different questions!

Maksim231197 [3]

Wave A would have higher amplitude

Hope this helps :D

7 0

3 years ago

Read 2 more answers

Friction occurs when the ____ and ____ of two surfaces grind against each other.

monitta

Friction occurs when the surfaces and heat of two surfaces grind against each other.

I think these are the answers

7 0

3 years ago

Calculate the charge that flows through the cell in 1 minute. Each filament lamp has a power of 3 W and a resistance of 12 Ω

lapo4ka [179]

Answer:

24 Coulumbs

Explanation:

Given data

time= 1 minute= 6 seconds

P=2 W

R= 12 ohm

We know that

P= I^2R

P/R= I^2

2/12= I^2

I^2= 0.166

I= √0.166

I= 0.4 amps

We know also that

Q= It

substitute

Q= 0.4*60

Q= 24 Columbs

Hence the charge is 24 Coulumbs

5 0

3 years ago

The muzzle velocity of a rifle bullet is 709 m s−1along the direction of motion. If the bullet weighs 35 g, and the uncertainty

nydimaria [60]

Answer:

Uncertainty in position of the bullet is $\Delta x=1.07\times 10^{-33}\ m$

Explanation:

It is given that,

Mass of the bullet, m = 35 g = 0.035 kg

Velocity of bullet, v = 709 m/s

The uncertainty in momentum is 0.20%. The momentum of the bullet is given by :

$p=mv$

$p=0.035\times 709=24.81\ kg-m/s$

Uncertainty in momentum is,

$\Delta p=0.2\%\ of\ 24.81$

$\Delta p=0.049$

We need to find the uncertainty in position. It can be calculated using Heisenberg uncertainty principal as :

$\Delta p.\Delta x\geq \dfrac{h}{4\pi}$

$\Delta x=\dfrac{h}{4\pi \Delta p}$

$\Delta x=\dfrac{6.62\times 10^{-34}}{4\pi \times 0.049}$

$\Delta x=1.07\times 10^{-33}\ m$

Hence, this is the required solution.

7 0

3 years ago

You can use any coordinate system you like in order to solve a projectile motion problem. To demonstrate the truth of this state

Aleks04 [339]

Explanation:

It is given that,

Height of the building, h = 44 m

Initial horizontal velocity, $u_x=ucos\theta=8.6\ m/s$

Initial vertical velocity, $u_y=usin\theta=10.5\ m/s$

It can be assumed to find the maximum height of the projectile and time taken to reach the maximum height.

The formula for the maximum height is given by :

$H=\dfrac{(u\ sin\theta)^2}{2g}$

g is the acceleration due to gravity

$H=\dfrac{(10.5)^2}{2\times 9.8}=5.625\ m$

The total maximum height, h' = h + H

$h'=44+5.625=49.625\ m$

The formula for the time of flight is given by :

$t_{max}=\dfrac{u\ sin\theta}{g}$

$t_{max}=\dfrac{10.5}{9.8}=1.07\ s$

Hence, this is the required solution.

3 0

3 years ago