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3 years ago

10

If you are at a train station and a train comes toward you, the train blows its whistle. as the train comes closer the whistle g

ets louder and as the train gets farther the whistle is quieter. What is this effect called?

1 answer:

Wittaler [7]3 years ago

4 0

This is called the Doppler Effect.

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Jorge hits a drum as hard as he can, and it makes a loud sound. Then he hits the same drum with less strength, and it makes a qu

Leviafan [203]

Answer:

when he uses more force to hit the drum then its makes a louder sound so the more force you hit the drum with then the louder it is.

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3 years ago

_____ is the horizontal change between two points on the line.

sattari [20]

The horizontal change between two points on a graph is called the 'run'.

The vertical change between two points is called the 'rise'.

6 0

3 years ago

Read 2 more answers

!! 50 points spent, easy points for you. 8th-grade science/physics !!

luda_lava [24]

Answer:

1.mirage

2.lens

3.concave lens

4.convex lens

5.index of refraction

Explanation:

IQ=999999

7 0

3 years ago

A person travels by car from one city to another with different constant speeds between pairs of cities. She drives for 35.0 min

Lubov Fominskaja [6]

Explanation:

Solution:

Let the time be

t1=35min = 0.58min

t2=10min=0.166min

t3=45min= 0.75min

t4=35min= 0.58min

let the velocities be

v1=100km/h

v2=55km/h

v3=35km/h

a. Determine the average speed for the trip. km/h

first we have to solve for the distance

S=s1+s2+s3

S= v1t1+v2t2+v3t3

S= 100*0.58+55*0.166+35*0.75

S=58+9.13+26.25

S=93.38km

V=S/t1+t2+t3+t4

V=93.38/0.58+0.166+0.75+0.58

V=93.38/2.076

V=44.98km/h

b. the distance is 93.38km

6 0

4 years ago

An artillery shell of mass 30 kg has a velocity of 250 m/s vertically upward. The shell explodes into two pieces; immediately af

olga_2 [115]

Answer:

9654.34 m

Explanation:

from conservation of momentum

$\begin{aligned}30 \times 250 &=-10 \times 120+20 \times V \\20 V &=30 \times 250+10 * 120 \\V &=\frac{30 \times 250+10 \times 120}{20}=435 \mathrm{~m} / \mathrm{s}\end{aligned}$

And from Conservation of Energy

$\frac{1}{2} m v^{2}=m g h\\h=\frac{v^{2}}{2 g}\\h=\frac{(435(m/s))^{2}}{2 \times 9.8(m/s^{2} )}\\h=9654.34 (m)$

7 0

2 years ago