Answer:
the horizontal force acting on rod is - 25.909 N
veritical force is 25.48 N
Explanation:
Given data:
mass of rod is m 2.6 kg
length of rod is 1.5 m
Hinge distance from the wire is 0.70 m
Apply torque law about hinge
Tension in the wire is
![T = \frac{[\frac{1.5}{2} cos 28 ]2.6 \times 9.8}{0.70}](https://tex.z-dn.net/?f=T%20%3D%20%5Cfrac%7B%5B%5Cfrac%7B1.5%7D%7B2%7D%20cos%2028%20%5D2.6%20%5Ctimes%209.8%7D%7B0.70%7D)
= -25.909 N
the horizontal force acting on rod is
Fx = T
FX = - 25.909 N
vertical force is
Fy = mg
Answer: she would move faster and more efficiently due to no friction
Explanation:
In the current brainly version, unfortunately you could not change your username.
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Answer: 0.4m
Explanation:
Given that:
Amplitude of wave = 2.0 m
Wavelength (λ)= ?
Frequency F = 500Hz
Speed V = 200 m/s
The wavelength is measured in metres, and represented by the symbol λ.
So, apply the formula:
Wavespeed V= Frequency F xwavelength λ
200m/s = 500Hz x λ
λ = 200m/s / 500Hz
λ = 0.4m
Thus, the wavelength is 0.4 metres
