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whirl a rock at the end of a string and it follows a circular path. if the string breaks, the tendency of the rock is to

1 answer:

8 0

Answer:

whirl a rock at the end of a string and it follows a circular path. if the string breaks, the tendency of the rock is to stop

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Two objects are dropped from rest from the same height. Object A falls through a distance Da and during a time t, and object B f

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Da=(1/4)Db

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t = Time taken

u = Initial velocity

v = Final velocity

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When s = Da, t = t

$s=ut+\frac{1}{2}at^2\\\Rightarrow Da=0\times t+\frac{1}{2}\times a\times t^2\\\Rightarrow Da=\frac{1}{2}at^2$

When s = Db, t = 2t

$s=ut+\frac{1}{2}at^2\\\Rightarrow Da=0\times t+\frac{1}{2}\times a\times (2t)^2\\\Rightarrow Db=\frac{1}{2}a4t^2$

Dividing the two equations

$\frac{Da}{Db}=\frac{\frac{1}{2}at^2}{\frac{1}{2}a4t^2}=\frac{1}{4}\\\Rightarrow \frac{Da}{Db}=\frac{1}{4}\\\Rightarrow Da=\frac{1}{4}Db$

Hence, Da=(1/4)Db

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3 years ago