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2 years ago

Can a higher mass-to-light ratio mean that there is gas and dust present in the system that is being analyzed?

Physics

1 answer:

kramer2 years ago

5 0

Answer:

mass-to-light ratio is the ratio of the mass of a body and the light output it has. it is represented by in terms of a single number and and tells us about the kind of stars making up the most luminous population in a galaxy. the mass-to-ratio of stars is greater than 1, for dark matter is 100 times high and very low for dust. higher mass-to-ratio mean that in a galaxy on average every solar mass emits a light less than the sun of the earth solar system does.

the large mass-to-light ratio shows that gas and dust is being analyzed.

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Where is the oldest operating lighthouse on the west coast on an island in america?

Vera_Pavlovna [14]

The Alcatraz Island light house off the coast of California's San Francisco Bay. It is located on the south side of the island.

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3 years ago

Does an object in inelastic collisions exert less force than elastic collisions?

Montano1993 [528]

Answer:

The object exerts <em>same</em> amount of force in elastic and inelastic collisions.

Explanation:

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2 years ago

Differentiate the followingy= 14t^2-t^2/2+5t-3dy/dt=?

STALIN [3.7K]

I'm going to assume you mean

$y = 14t^2 - \dfrac{t^2}{2+5t} - 3$

Taking the derivative with respect to <em>t</em> on both sides gives

$\dfrac{\mathrm dy}{\mathrm dt} = 2\cdot14t - \dfrac{(2+5t)(2t)-t^2(5)}{(2+5t)^2} - 0 \\\\ \dfrac{\mathrm dy}{\mathrm dt} = \boxed{28t - \dfrac{4t+5t^2}{(2+5t)^2}}$

You could go on to expand the rational expression into partial fractions. One way to do this:

$\dfrac{5t^2 + 4t}{(2 + 5t)^2} = \dfrac{t(5t+2) + 2t}{(2+5t)^2} \\\\= \dfrac{t}{2+5t} + \dfrac{2t}{(2+5t)^2} \\\\= \dfrac15 \cdot \dfrac{t}{\frac25+t} + \dfrac{2t}{(2+5t)^2} \\\\ = \dfrac15 \cdot \dfrac{t+\frac25-\frac25}{\frac25+t} + \dfrac{2t}{(2+5t)^2} \\\\ = \dfrac15 \left(1 - \dfrac{2}{2+5t}\right) + \dfrac{2t}{(2+5t)^2} \\\\ = \dfrac15 - \dfrac{2}{10+25t}+ \dfrac{2t}{(2+5t)^2}$

and this would give

$\dfrac{\mathrm dy}{\mathrm dt} = 28t - \dfrac15 + \dfrac2{10+25t} - \dfrac{2t}{(2+5t)^2}$

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2 years ago

What metals were the alchemist trying to produce ?did they succeed ?

xeze [42]

The alchemists were trying to convert lead and copper into gold.

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2 years ago

Read 2 more answers

A transverse wave has an amplitude of 2.4m. What is the vertical distance, in meters, between the top of a Crest and the bottom

Alex17521 [72]

Answer:

4.8 m

Explanation:

A transverse wave is a wave in which the oscillation of the particles occur in a direction perpendicular to the direction of motion of the wave.

The amplitude of a transverse wave is the maximum displacement of the wave with respect to the equilibrium position.

The crest of a wave is the position of maximum displacement on the positive side, while the trough of a wave is the position of maximum displacement on the negative side.

This means that the amplitude of a wave is equal to the distance between a crest (or a trough) and the equilibrium position.

Therefore, we have:

$d=2A$

where:

d is the distance between the top of a crest and the bottom of a trough

A is the amplitude of the wave

Here we have:

A = 2.4 m

So, we find

$d=2\cdot 2.4 = 4.8 m$

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3 years ago