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3 years ago

Matter is made up of very small particles

Physics

1 answer:

aivan3 [116]3 years ago

6 0

<h2>Answer:</h2>

The given statement on matter is true.

<h2>Explanation:</h2>

The matter refers to any substance or object that occupies volume. A matter always has mass which are composed of huge number of microscopic particles named atoms. The atoms are comprises subatomic particle, however, it does not contain particle like photons (massless particle).

The matter is classified widely based on many factors and based on its existence it is classified as liquid solid, and fluid. Depending on the structure, the matter is classified into baryonic matter, hadronic matter, degenerate matter, and strange matter.

Thus, the matter comprises tiny particles.

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area of the leaf and length of the fiber

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area = volume / thickness

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3 years ago

A 1.60 m cylindrical rod of diameter 0.550 cm is connected to a power supply that maintains a constant potential difference of 1

bija089 [108]

Answer:

Part a)

$\rho = 1.35 \times 10^{-5}$

Part b)

$\alpha = 1.12 \times 10^{-3}$

Explanation:

Part a)

Length of the rod is 1.60 m

diameter = 0.550 cm

now if the current in the ammeter is given as

$i = 18.7 A$

V = 17.0 volts

now we will have

$V = I R$

$17.0 = 18.7 R$

R = 0.91 ohm

now we know that

$R = \rho \frac{L}{A}$

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$\rho = 1.35 \times 10^{-5}$

Part b)

Now at higher temperature we have

$V = I R$

$17.0 = 17.3 R$

R = 0.98 ohm

now we know that

$R = \rho \frac{L}{A}$

$0.98 = \rho' \frac{1.60}{\pi(0.275\times 10^{-2})^2}$

$\rho' = 1.46 \times 10^{-5}$

so we will have

$\rho' = \rho(1 + \alpha \Delta T)$

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Answer:

Part a)

$i = 1.55 A$

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$v_d = 1.4 \times 10^{-4} m/s$

Explanation:

Part a)

As we know that current density is defined as

$j = \frac{i}{A}$

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Part b)

now we have

$j = nev_d$

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$n = 8.5 \times 10^{28}$

$e = 1.6 \times 10^{-19} C$

so we have

$1.90 \times 10^6 = (8.5 \times 10^{28})(1.6 \times 10^{-19})v_d$

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4 years ago