Due to the Composition, different asteroids reflect different percentages of the light falling on them.
What are Asteroids:
- Asteroids are small, rocky objects that orbit the Sun. Although asteroids orbit the Sun like planets, they are much smaller than planets.
- Asteroids are generally made up of rocky material, metals and their size are large in comparison to comets. Asteroid belt is found between Jupiter and Mars.
Composition of Asteroids:
- Most of the asteroids in the Main Belt are made of rock and stone.
- The remaining asteroids are made up of a mix of these, along with carbon-rich materials. Some of the more distant asteroids tend to contain more ices.
We determine reflectivity of asteroids by comparing the brightness of light in the visible spectrum to the brightness of light in the infrared spectrum. The light shining from asteroids is reflected sunlight.
Hence we can say that,
Due to the Composition, different asteroids reflect different percentages of the light falling on them.
Learn more about Asteroids here:
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Answer:
Angular momentum = 0.7 kg.m²/s
Angular velocity = 583.3 rad/s
Explanation:
1. The torque τ is related to the angular momentum L by the relation
τ = ΔL/Δt
ΔL = τΔt
τ = 10 N. m
Δt = 70 ms = 70 × 10⁻³s
ΔL = (10 N. m) × (70 × 10⁻³s) = 700 × 10⁻³ kg.m²/s = 0.7 kg.m²/s
2. The rotational inertia I relates the angular momentum L to the angular velocity w
L = Iw
w = L/I
L = 0.7 kg.m²/s
I = 1.2 × 10⁻³ kg.m²
w = (0.7 kg.m²/s)/(1.2 × 10⁻³ kg.m²) = 583.3 rad/s
Answer:
The hummingbird travels the total distance is 10 m
Explanation:
Given that,
A hummingbird flies forward and backward.
According to figure,
We know that,
The total distance is equal to the sum of all distance.
Forward direction is positive and backward direction is negative.
We need to calculate the hummingbird travels the total distance
Using figure,

Put the value into the formula


Hence, The hummingbird travels the total distance is 10 m.
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Answer:
C = 1.01
Explanation:
Given that,
Mass, m = 75 kg
The terminal velocity of the mass, 
Area of cross section, 
We need to find the drag coefficient. At terminal velocity, the weight is balanced by the drag on the object. So,
R = W
or

Where
is the density of air = 1.225 kg/m³
C is drag coefficient
So,

So, the drag coefficient is 1.01.