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3 years ago

13

An athlete stretches a spring an extra 28.6 cm beyond its initial length. how much energy has he transferred to the spring, if t

he spring constant is 52.9 n/cm?

1 answer:

g100num [7]3 years ago

6 0

PE = 0.5 × k × x²

PE potential Energy
k spring constant
x stretch/compression of the spring

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