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Rudiy27
3 years ago
13

An athlete stretches a spring an extra 28.6 cm beyond its initial length. how much energy has he transferred to the spring, if t

he spring constant is 52.9 n/cm?
Physics
1 answer:
g100num [7]3 years ago
6 0
PE = 0.5 × k × x²

PE potential Energy
k spring constant
x stretch/compression of the spring
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3 years ago
True or false conceptual physics 2 questions from chapter 25.
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Answer:

Explanation:

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3 0
3 years ago
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Natasha_Volkova [10]

Answer:

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m = 230 g = 0.230 kg, x = 8.2 cm

in 13 oscillations, time taken = 19 s

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T = 2\pi \sqrt{\frac{m}{k}}

1.46 = 2\pi \sqrt{\frac{0.230}{k}}

0.054 = 0.230 / k

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V=IR. This is the formula that you can use to figure this question out. Because the voltage stays the same and the current decreases, this means that the resistance has increased.
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3 years ago
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