Ask question

Ask question

All categories

2 years ago

13

An athlete stretches a spring an extra 28.6 cm beyond its initial length. how much energy has he transferred to the spring, if t

he spring constant is 52.9 n/cm?

1 answer:

g100num [7]2 years ago

6 0

PE = 0.5 × k × x²

PE potential Energy
k spring constant
x stretch/compression of the spring

You might be interested in

You matter .<br>Until you Multiply yerself by the speed of Light Squared. <br>Then you Energy.<br>

iragen [17]

Answer:

Hellow ❤️

.

.

Gooood Morning

6 0

2 years ago

Read 2 more answers

A vector has components Ax = 12.0 m and Ay= 5.00 m. What is the angle that vector A makes with the x-axis?a. 67.4ob. 32.6oc. 22.

antoniya [11.8K]

Answer:

C.22.6°

Explanation:

Ax = ACosθ,

A = Ax/Cosθ .....equ1

Ay = Asinθ,

A= Ay/sinθ .....equ 2

equate equation 1 and 2.

Ax/Cosθ = Ay/sinθ

Ax = 12.0 m, Ay= 5.00 m

12/Cosθ = 5/sinθ

θ = 22.6°

5 0

2 years ago

Two parallel plates have equal and opposite charges. When the space between the plates is evacuated, the electric field is E= 3.

svetlana [45]

Explanation:

The given data is as follows.

Electric field between plates without dielectric, $E_{1} = 3.50 \times 10^{5} V/m$

Electric field between the plates with dielectric, $E_{2} = 2.40 \times 10^{5} V/m$ .

Permittivity of free space, $\epsilon_{o}$ = $8.85 \times 10^{-12} C^{2}/Nm^{2}$

Now, we will determine the charge density as follows.

$\sigma_{i} = \epsilon_{o}(E_{1} - E_{2})$

= $8.85 \times 10^{-12} \times (3.50 \times 10^{5} - 2.40 \times 10^{5})$

= $9.735 \times 10^{-7} C/m^{2}$

Thus, we can conclude that the charge density on each surface of the dielectric is $9.735 \times 10^{-7} C/m^{2}$ .

6 0

2 years ago

Aluminum oxide can be produced during rocket launches. Show that the sum of positive and negative charges in a unit of Al2O3 equ

Triss [41]

Answer:

The sum of positive and negative charges in a unit of Al2O3 equals zero.

Aluminium has a charge of +3 while Oxygen has a charge of -2 on each ion.

Al203 has 2 Al atoms and 3 O atoms.

Charge on Al2O3 = 2(charge on Al ion) + 3(charge on O ion)

= 2(3) + 3(-2)

= 6 - 6

= 0

Explanation:

Aluminium has 3 electrons in the outermost shell and has the tendency to lose those 3 electrons to form a positive ion and have a complete outermost shell.

Whereas, Oxygen has 6 electrons in the outermost and has the tendency to accept two more electrons to form a negative ion and have a complete outermost shell.

4 0

3 years ago

Buco novia de 15n de edad

Zigmanuir [339]

Yo tengo quince y soy de cali y estoy viviendo en mexico

4 0

2 years ago