Gravitational potential energy=mass*gravitational acceleration*height
Kinetic energy = 0.5*mass*velocity²
So with the given data
K.E 0.5*1*x²=12.5 v²=12.5÷(0.5*1)
v=√12.5÷(0.5*1) v=5
GPE mass*gravitational acceleration*height
1*9.81*h=98
h=98÷(9.81*1)
h= 9.98 m
Answer:
1 minute 36.85 seconds
Explanation:
First we need to convert the miles into meters, as the demanded result should be in meters.
1 mile = 1,609.34 meters
Also, 6.5 minutes should be converted into seconds.
1 minute = 60 seconds
6.5 x 60 = 390 seconds
Now we need to divide the miles with the seconds to see how much meters have been run in a second.
1,609.34 / 390 = 4.13 meters
The suggested meters now should be divided with the distance run in one second.
400 / 4.13 = 96.85 seconds
So we get a result of 96.85 seconds, or 1 minute 36.85 seconds.
Answer:
-30 °C
Explanation:
First, we have to calculate the molality (m) of the solution. If the solution is 50% C₂H₆O₂ by mass. It means that in 100 g of solution, the are 50 g of solute (C₂H₆O₂) and 50 g of solvent (water).
The molar mass of C₂H₆O₂ is 62.07 g/mol. The moles of solute are:
50 g × (1 mol / 62.07 g) = 0.81 mol
The mass of the solvent is 50 g = 0.050 kg.
The molality is:
m = 0.81 mol / 0.050 kg = 16 m
The freezing-point depression (ΔT) can be calculated using the following expression.
ΔT = Kf × m = (1.86 °C/m) × 16 m = 30 °C
where,
Kf: freezing-point constant
The normal freezing point for water is 0°C. The freezing point of the radiator fluid is:
0°C - 30°C = -30 °C
Answer:
Explanation:
The movement of a body can be analyzed using New's first law. In an inertial frame (without acceleration) every body is kept at rest or moving at constant speed until there is an external force that changes this state
Let's analyze these cases in the framework of this first law
a) If the vehicle is going at constant speed the two bodies (the egg and the hands) do not change movement so he had returned to the hands
b) If the vehicle accelerates the passenger goes faster, but the egg that is not subject to anything does not change the movement, so it falls behind the passenger
c) If the vehicle slows down, the passenger reduces its speed and the distance traveled in time, but the egg that is not attached follows its movement and falls in front of the passenger.
