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Soloha48 [4]
3 years ago
8

Water is pumped through a pipe of diameter 15.0 cm, from the Colorado River up to Grand Canyon Village, located on the rim of th

e canyon. The river is at an elevation of 564 m, and the village is at an elevation of 2096 m. What is the minimum pressure at which the water must be pumped if it is to arrive at the village?
Physics
1 answer:
Aleksandr [31]3 years ago
8 0

Answer:

p= 1.50289×10⁷ N/m²

Explanation:

Given

HA = (564 m)................(River Elevation)

HB = (2096 m).............(Village Elevation)

Area = A =(π/4){Diameter}² = (π/4){0.15 m}² = 0.017671 m²

ρ = (1 gram/cm³) = (1000 kg/m³)........(Water Density)

p(pressure)=?

Solution

p=PA - PB

p= ρ*g*HB - ρ*g*HA

p= (ρ*g)*(HB - HA)

p= (1000×9.81 )×{2096  - 564}  

p= 1.50289×10⁷ N/m²

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elixir [45]

B  acid + base    →  water + salt

Explanation:

The best equation that represents a neutralization reaction is:

                      acid + base    →  water + salt

In a neutralization reaction, an acid reacts with a base to produce salt and water only.

Here, hydrogen combines with hydroxide to form water.

Titration is usually used to carry out this reaction in the laboratory.

An indicator is added to the base and at end the color of the reaction changes.

At this point the acids have completely been neutralized with the base.

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Marysya12 [62]

Answer:

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4 0
3 years ago
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What is the reflectivity of a glass surface (n =1.5) in air (n = 1) at an 45° for (a) S-polarized light and (b) P-polarized ligh
Goshia [24]

Answer:

a) R_s = 0.092

b) R_p = 0.085

Explanation:

given,

n =1.5 for glass surface

n = 1 for air

incidence angle = 45°

using Fresnel equation of reflectivity of S and P polarized light

R_s=\left | \dfrac{n_1cos\theta_i-n_2cos\theta_t}{n_1cos\theta_i+n_2cos\theta_t} \right |^2\\R_p=\left | \dfrac{n_1cos\theta_t-n_2cos\theta_i}{n_1cos\theta_t+n_2cos\theta_i} \right |^2

using snell's law to calculate θ t

sin \theta_t = \dfrac{n_1sin\theta_i}{n_2}=\dfrac{sin45^0}{1.5}=\dfrac{\sqrt{2}}{3}

cos \theta_t =\sqrt{1-sin^2\theta_t} = \dfrac{sqrt{7}}{3}

a) R_s=\left | \dfrac{\dfrac{1}{\sqrt{2}}-\dfrac{1.5\sqrt{7}}{3}}{\dfrac{1}{\sqrt{2}}+\dfrac{1.5\sqrt{7}}{3}} \right |^2

R_s = 0.092

b) R_p=\left | \dfrac{\dfrac{\sqrt{7}}{3}-\dfrac{1.5}{\sqrt{2}}}{\dfrac{\sqrt{7}}{3}+\dfrac{1.5}{\sqrt{2}}} \right |^2

R_p = 0.085

3 0
3 years ago
PLEASE HELP! DUE DATE IS TODAY
g100num [7]

Answer:

<u>Question 2</u>

<u>Part (a)</u>

Chlorine:  type of compound = chloride

Oxygen:  type of compound = oxide

<u>Part (b)</u>

The iron reacts with water and oxygen to form rust.

A water molecule is made up of two hydrogen atoms joined to one oxygen atom:  Di-hydrogen oxide.

<u>Question 3</u>

This circuit is in parallel.

The current in a parallel circuit splits into different branches then combines again before it goes back into the supply.

We are told that A₁ = 0.8 A

As the lamps have <u>equal resistance</u>, the current splits equally:

A₂ = 0.4 A

A₃ = 0.4 A

Then combines again:

A₄ = 0.8 A

4 0
2 years ago
Ex 1) A Major League baseball pitcher throws a baseball straight up into the air and the ball travels for 4
nlexa [21]

Answer:

52 / 4 = 13 m/s

Explanation:

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3 years ago
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