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3 years ago

Define 1 unit electricity

Physics

1 answer:

Tomtit [17]3 years ago

4 0

Answer:

A unit is represented in kWH or Kilowatt Hour. This is the actual electricity or energy used. If you use 1000 Watts or 1 Kilowatt of power for 1 hour then you consume 1 unit or 1 Kilowatt-Hour (kWh) of electricity.

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Katie is walking in an orange grove. She looks at all of the orange trees. She wants to find out how many seeds are in each oran

aliya0001 [1]

Answer:

What she can do to collect the data is;

B. Gather a few oranges and see how many seeds are in each

Explanation:

The quantity Katie wants to find out is the number of seeds contained in each orange

Therefore, the required population = The number of seeds in a given orange

The method of estimation of the number of seeds per orange is sampling method, whereby the number of seeds in each of the orange in the sample is used to as an hypothesis as to the number of seeds expected in each orange of the entire population.

Therefore, in order to collect the data, she can gather a few oranges and see how many seeds are in each.

3 0

3 years ago

Two objects have the same velocity. These two objects have different masses. Which object will

kogti [31]

Answer:

The object with the greater mass will have the greater momentum

Explanation:

The momentum of an object with mass m, moving with velocity , is given by the formula

M = mv

Since both objects have the same velocity v, it is clear that the object with the bigger mass will have the greater momentum

6 0

2 years ago

When a positively charged body touches a neutral body, the neutral body will

PtichkaEL [24]

Become more positive instead of negative

7 0

3 years ago

Calculate the acceleration of gravity as a function of depth in the earth (assume it is a sphere). You may use an average densit

Ber [7]

Solution :

Acceleration due to gravity of the earth, g $=\frac{GM}{R^2}$

$g=\frac{G(4/3 \pi R^2 \rho)}{R^2}=G(4/3 \pi R \rho)$

Acceleration due to gravity at 1000 km depths is :

$g=G\left(\frac{4}{3}\pi (R-d) \rho\right)$

$g=6.67 \times 10^{-11}\left(\frac{4}{3}\times 3.14 \times (6371-1000) \times 5.5 \times 10^3\right)$

$= 822486 \times 10^{-8}$

$=0.822 \times 10^{-2} \ km/s$

= 8.23 m/s

Acceleration due to gravity at 2000 km depths is :

$g=G\left(\frac{4}{3}\pi (R-d) \rho\right)$

$g=6.67 \times 10^{-11}\left(\frac{4}{3}\times 3.14 \times (6371-2000) \times 5.5 \times 10^3\right)$

$= 673552 \times 10^{-8}$

$=0.673 \times 10^{-2} \ km/s$

= 6.73 m/s

Acceleration due to gravity at 3000 km depths is :

$g=G\left(\frac{4}{3}\pi (R-d) \rho\right)$

$g=6.67 \times 10^{-11}\left(\frac{4}{3}\times 3.14 \times (6371-3000) \times 5.5 \times 10^3\right)$

$= 3371 \times 153.86 \times 10^{-8}$

= 5.18 m/s

Acceleration due to gravity at 4000 km depths is :

$g=G\left(\frac{4}{3}\pi (R-d) \rho\right)$

$g=6.67 \times 10^{-11}\left(\frac{4}{3}\times 3.14 \times (6371-4000) \times 5.5 \times 10^3\right)$

$= 153.84 \times 2371 \times 10^{-8}$

$=0.364 \times 10^{-2} \ km/s$

= 3.64 m/s

3 0

3 years ago

abruzzese [7]

Answer:

I think they use it at night because they want to avoid involving themselves in road accident while crossing the street. When there are reflective strips on their clothes, drivers do notice them even at far ends of the street since the strips will reflect the rays from the car lights to the driver,hence, the driver notifies that there is a pedestrian crossing and therefore slows down.

3 0

3 years ago

Define 1 unit electricity​

Define 1 unit electricity