How much heat is needed to change the temperature of 3 grams of gold (c = 0.129 ) from 21°C to 363°C? The answer is expressed to
2 answers:
The correct answer to the question is : B) 132 Joules.
EXPLANATION :
As per the question, the mass of the gold m = 3 gram.
The initial temperature of the gold T = 21 degree celsius.
The final temperature of the gold T' = 363 degree celsius.
Hence, the change in temperature dT = T' - T
= 363 - 21 degree celsius
= 342 degree celsius.
The specific heat of the gold is given as c =
We are asked to calculate the heat required ( dQ ) to raise the temperature of gold.
The heat required for this is calculated as -
dQ = mcDT
= 3 × 342 × 0.129 J
= 132.354 J
≈ 132 J
Hence, the correct answer is 132 J.
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Answer:
1.
2.
Explanation:
1. According to Newton's law of motion, the puck motion is affected by the acceleration, which is generated by the push force F.
In Newton's 2nd law: F = ma
where m is the mass of the object and a is the resulted acceleration. So in the 2nd experiment, if we double the mass, a would be reduced by half.
Since the puck start from rest, in the 1st experiment, to achieve speed of v it would take t time
Now that acceleration is halved:
You would need to push for twice amount of time
2. The distance traveled by the puck is as the following equation:
So if the acceleration is halved while maintaining the same d:
As , then
. Also
So t increased by 1.14
Answer:
162500000.
Explanation:
Given that
Diameter of the wire , d= 1.8 mm
The length of the wire ,L = 15 cm
Current ,I = 260 m A
The charge on the electron ,e= 1.6 x 10⁻¹⁹ C
We know that Current I is given as
I=Current
q=Charge
t=time
q= I t
q= 260 m t
The total number of electron = n
q= n e
n=162500000 t
The number of electron passe per second will be 162500000.