The energy transform into the energy of ATP
Answer:
v = 4.18 m/s
Explanation:
given,
frequency of the alarm = 872.10 Hz
after passing car frequency she hear = 851.10 Hz
Speed of sound = 343 m/s
speed of the jogger = ?
speed of the
![v_f = \dfrac{872.10-851.10}{2}](https://tex.z-dn.net/?f=v_f%20%3D%20%5Cdfrac%7B872.10-851.10%7D%7B2%7D)
![v_f =10.5\ Hz](https://tex.z-dn.net/?f=v_f%20%3D10.5%5C%20Hz)
v_o = 872.1 - 10.5
![V_0 = 861.6\ Hz](https://tex.z-dn.net/?f=V_0%20%3D%20861.6%5C%20Hz)
The speed of jogger
![v = \dfrac{v_1 \times 343}{v_0}-343](https://tex.z-dn.net/?f=v%20%3D%20%5Cdfrac%7Bv_1%20%5Ctimes%20343%7D%7Bv_0%7D-343)
![v = \dfrac{872.1 \times 343}{861.6}-343](https://tex.z-dn.net/?f=v%20%3D%20%5Cdfrac%7B872.1%20%5Ctimes%20343%7D%7B861.6%7D-343)
v = 4.18 m/s
<span>Machines simply transmit mechanical work from one part of a device to another part. A machine produces force and controls the direction and the motion of force, but it cannot create energy. A machine's ability to do work is measured by two factors. These are (1) mechanical advantage and (2) efficiency. </span>
Answer:
y = 428.67 m and x all = 1513.68 m
Explanation:
This problem of kinematics can be divided into two parts: a first part when the rockets work a second as a parabolic launch.
Let's do the first part, let's calculate the speed just when the engines turn off
vf = v₀ + at
vf = 78 + at
vf = 78 +12 3
vf = 114 m / s
This is the speed with which the second part begins vo = 114 m / s with an Angle of 38º
Also at this time a distance is displaced, we calculate the distance traveled (in the direction of the acceleration)
d = v₀ t + ½ a t²
d = 78 3 + ½ 12 3²
d = 288 m
Let's use trigonometry to find the components
x₀ = d cos 38 = 288 cos 38
y₀ = d sin38 = 288 sin38
x₀ = 226.95 m
y₀ = 177.31 m
Second part
Let's calculate the maximum height, at this point its vertical speed is zero (vfy = 0)
Let's decompose the initial velocity using trigonometry
vₓ = v₀ cos 38
= v₀ sin38
vₓ = 114 cos 38
= 114 sin38
vₓ = 89.83 m / s
= 70.19 m / s
² =
² - 2g (y -y₀)
0 =
² -2g (y -yo)
y-y₀ =
² / 2g
y-y₀ = 70.19²/2 9.8
y = 251.36 + y₀
y = 251.36 + 177.31
y = 428.67 m
This is the maximum height from the point where the movement began, that is, the ground.
Now let's calculate the range
R = vo² sin 2θ / g
R = 114² sin 2 38 /9.8
R = 1286.73 m
This is the scope of the parabolic movement, we must add the horizontal distance traveled in the first part
x all = R + xo
x all = 1286.73 + 226.95
x all = 1513.68 m
Answer:
a)
The magnitude of the attractive force is ![14.29N](https://tex.z-dn.net/?f=14.29N)
b)
The magnitude of the repulsive force is ![0.357N](https://tex.z-dn.net/?f=0.357N)
c)
The magnitude of the net force is ![0N](https://tex.z-dn.net/?f=0N)
Explanation:
The explanation is shown on the first and second uploaded image