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Mariana [72]
3 years ago
13

Which of the following statements is true? Question 5 options: Nuclear decay rates vary with the conditions of the reaction, but

chemical reaction rates do not. Neither chemical reaction rates nor nuclear decay rates vary with the conditions of the reaction. Both chemical reaction rates and nuclear decay rates vary with the conditions of the reaction. Chemical reaction rates vary with the conditions of the reaction, but nuclear decay rates do not
Chemistry
1 answer:
andrezito [222]3 years ago
6 0

Answer: I believe its a Chemical reaction rates vary with the conditions of the change, but nuclear decay rates do not.

Explanation:

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The most common form of energy encountered in chemical reactions is _____. Select one:
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Why do we use 51.0mL of NaOH but only 50.0mL of HCl?
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Answer

Na OH reacts with H Cl and forms Na Cl and H₂O

NaOH + HCl   →   NaCl + H₂O                                              

Here we can see that  1 mole of NaOH reacting with 1 mole of HCl and forming 1 mole of NaCl and 1 mole of H₂O

when  NaOH and HCl are added together in equal amount then they will completely neutralize each other but NaOH is hygroscopic in nature which means it can absorb water from air so it will not be weighted accurately.

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3 years ago
Write the complete balanced equation for the neutralization reaction that occurs when aqueous hydroiodic acid, HI, and sodium hy
Serhud [2]

Answer:

H+ ( aq ) + HCO3- ( aq ) ------> H2O( l ) + CO2 ( g )

Explanation:

The complete reaction when hydroiodic acid and sodium hydrogen carbonate combine, would be as follows -

HI + NaHCO3 ----> NaI + H2O + CO2

net reaction

H2CO3 is highly unstable, and thus decomposes into the water and carbon dioxide you see present as the reactants. If you didn't know already, H2CO3 is also reffered to as carbonic acid. The rest of the elements present on the reactant side are Iodine and Sodium, which is why they are present on the product side as NaI.

Let me include the " physical states " in this reaction as well -

HI ( aq ) + NaHCO3 ( aq ) ----> NaI ( aq ) + H2O ( l ) + CO2 ( g )

Now the complete ionic equation would simply be each compound present as ions in an aqueous solution, so there is no need for an explanation on this step -

H+ ( aq ) + I- ( aq ) + Na+ ( aq ) + HCO3- ( aq ) -------> Na+ ( aq ) + I- ( aq ) + H2O( l ) + CO2 ( g )

The spectator ions in this reaction are I- and Na+, so canceling them out, you would receive the following net ionic equation -

H+ ( aq ) + HCO3- ( aq ) ------> H2O( l ) + CO2 ( g )

<u><em>Hope that helps!</em></u>

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Answer:

A

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