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Gemiola [76]
3 years ago
7

What is the chemical formula of tin(IV) chloride pentahydrate?

Chemistry
1 answer:
Vladimir [108]3 years ago
4 0

Answer:

SnCl4 * 5H2O

Explanation:

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What Is the answers?
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Answer:

oxygen is responsible for rusting

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An atom that normally has __________ electrons in its outer (valence) shell tends not to form chemical bonds with other atoms.
goblinko [34]
8 valence shell electrons.
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What happens to the population size of each of the pond organisms when the perch population size is decreased? How many of the s
lana [24]
I found a presentation of Food web of a pond that will greatly connect with the above problem.  http://www.eduweb.com/portfolio/earthsystems/food/foodweb4.html

Normal setting:
Species        Pop. size
Blue heron   Medium
Perch            Medium
Bass              Medium
Minnows      Medium
Inverts          Medium
Algae           Medium

If PERCH population size decreases, 
Species        Pop. sizeBlue heron   LowPerch            LowBass              MediumMinnows      HighInverts          HighAlgae           Low

As you can see, 4 other species are affected when the Perch population size decreased. Bass is not affected. 
8 0
3 years ago
How many atoms are in oxygen
Aleonysh [2.5K]
There are only 2 atoms in an Oxygen molecule
4 0
3 years ago
What mass of Sodium Chloride is required to make 100.0 mL of 3.0 M solution?
Julli [10]

Answer:

17.55 g of NaCl

Explanation:

The following data were obtained from the question:

Molarity = 3 M

Volume = 100.0 mL

Mass of NaCl =..?

Next, we shall convert 100.0 mL to L. This can be obtained as follow:

1000 mL = 1 L

Therefore,

100 mL = 100/1000

100 mL = 0.1 L

Therefore, 100 mL is equivalent to 0.1 L.

Next, we shall determine the number of mole NaCl in the solution. This can be obtained as follow:

Molarity = 3 M

Volume = 0.1 L

Mole of NaCl =?

Molarity = mole /Volume

3 = mole of NaCl /0.1

Cross multiply

Mole of NaCl = 3 × 0.1

Mole of NaCl = 0.3 mole

Finally, we determine the mass of NaCl required to prepare the solution as follow:

Mole of NaCl = 0.3 mole

Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol

Mass of NaCl =?

Mole = mass /Molar mass

0.3 = mass of NaCl /58.5

Cross multiply

Mass of NaCl = 0.3 × 58.5

Mass of NaCl = 17.55 g

Therefore, 17.55 g of NaCl is needed to prepare the solution.

5 0
3 years ago
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