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joja [24]
3 years ago
11

Define organic chemistry and inorganic chemistry.

Chemistry
2 answers:
Fudgin [204]3 years ago
5 0
Organic Chemistry: the chemistry of carbon compounds


Inorganic Chemistry: deals with chemicals 
MrRissso [65]3 years ago
3 0
Organic is safer inorganic is the same but less better
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Explanation: that is .....

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Which of the following is a structure of a cow?
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None of the above.

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3 years ago
A balloon is floating around outside your window. The temperature outside is 31 ∘C , and the air pressure is 0.700 atm . Your ne
DochEvi [55]

Answer:

the volume of gas inside this balloon = 146.3 L

Explanation:

Given that:

The temperature T = 31 °C = ( 31 + 273.15 )K = 304.15 K

The air pressure P = 0.700 atm

number of moles of gas n = 4.10 moles

Gas constant = 0.0821 L atm/K/mol

The objective is to calculate the volume of the gas inside the ballon.

Using the Ideal gas equation

PV = nRT

V = nRT/P

V = (4.10×0.0821×304.15)/0.700

V = 102.3799/0.700

V = 146.257 L

V = 146.3 L

Thus, the volume of gas inside this balloon = 146.3 L

3 0
3 years ago
Match the layers of the atmosphere
Ira Lisetskai [31]

Answer:

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7 0
3 years ago
Una masa de aire ocupa un volumen de5litro a una temperatura de 120c Cual será el nuevo volumen si la temperatura se reduce ala
zalisa [80]

Answer:

1. V_2=2.5L

2. V_2=8000mL

3. V_2=176.3L

Explanation:

¡Hola!

En este caso, dada la información para estos problemas, procedemos de la siguiente manera, basado en las leyes de los gases ideales:

1. Una masa de aire ocupa un volumen de 5 litros a una temperatura de 120 °C Cual será el nuevo volumen si la temperatura se reduce a la mitad:

Aqui, utilizamos la ley de Charles, asegurándonos que la temperatura está en Kelvin:

\frac{T_2}{V_2} =\frac{T_1}{V_1} \\\\V_2 =\frac{V_1T_2}{T_1} \\\\V_2 =\frac{5L*196.5K}{393K} \\\\V_2=2.5L

2. Un gas ideal ocupa un volumen de 4000 ml a una presión absoluta de 1500 kilo pascal Cual será la presión si el gas es comprimido lentamente hasta 750 kilo pascal a temperatura constante?

Aquí, utilizamos la ley de Boyle, dado que la temperatura se mantiene constante, calculando el volumen, ya que lo que se da es la presión final:

\neq P_2V_2=P_1V_1\\\\V_2=\frac{P_1V_1}{P_2}\\\\ V_2=\frac{4000mL*1500kPa}{750kPa}\\\\V_2=8000mL

3. Un gas ocupa un volumen de 200 litros a 95°C y 782 mmHg Cual será el volumen ocupado por dicho gas a 65°C y 815 mmHg:

Aquí, utilizamos la ley combinada de los gases ideales, asegurándonos que las temperaturas están en Kelvin:

\frac{T_2}{P_2V_2} =\frac{T_1}{P_1V_1} \\\\V_2 =\frac{P_1V_1T_2}{P_2T_1} \\\\V_2 =\frac{782mmHg*200L*338K}{815mmHg*368K}\\\\V_2=176.3L

¡Saludos!

6 0
3 years ago
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