Answer: NO2
Explanation:
N O
Divide each by its 25.93 74.07
mass number 14 16
2 4
Divide both by the 2 2
smaller (i.e. 2) 1 2
Therefore, the empirical formula = NO2
The activity coefficient of h is 0.05
The ph of the solution is 2.08
To find the activity coefficient, apply the concept of ionic equilibrium
h( activity coefficient)= 1/2CZ²
C is the concentration of species
Z is the charge on individual species
<em>h= 1/2( 0.01 x1²+ 0.04x (-1)²+0.01 x1²+0.04x (-1)²)</em>
<em>h= 0.05 </em>
For the pH of the solution, apply the formula
<em>pH= -log( H⁺x0.83)</em>
<em>pH = - log(0.01x0.83)</em>
<em>= 2.08</em>
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Answer:
D) The equilibrium lies far to the left
Explanation:
According to the law of mass action, the equilibrium constant K for the reaction at 373K can be calculated as follows:
K =
= 2.19×10^{-10}
([X] means = concentration of X)
This means that in the equilibrium the concentration of the reactant (that is in the denominator) will be much higher (around 10^{10} fold) than the concentrations of the products (that are in the numerator), and this means that the equilibrium lies far to the left (to the reactants side) as very small amount of product is being formed.