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Sergio [31]
3 years ago
14

Nicolaus Copernicus was a Polish astronomer who is best known for the theory that the sun is near the center of the universe and

that the earth and other planets revolve around it. Copernicus did not believe that the planets were influenced by or revolved due to the sun; instead he believed that the sun was located near the center of the universe and that it was this center which influenced those bodies and caused them to revolve. When this theory was first published, the scientific community did not accept it. Which reason BEST explains the reason for rejection of this theory? A) It was not published until his death. B) It was not understood by scientific world. C) It lacked sufficient evidence and explanation. D) It lacked practical examples in supporting theory.
Physics
1 answer:
abruzzese [7]3 years ago
4 0

Answer:B) It was not understood by scientific world.

Explanation:

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A solid conducting sphere with radius R carries a positive total charge Q. The sphere is surrounded by an insulating shell with
Illusion [34]

Answer:

Explanation:

Volume of the insulating shell is,

V_{shell}=\frac{4}{3}\pi(R^3_2-R^3_1)

Charge density of the shell is,

\rho=\frac{Q_{shell}}{\frac{4}{3}\pi(R^3_2-R^3_1)}

Here, R_2 =2R, R_1 =R \,and\, Q_{shell} =-Q

\rho=\frac{Q_{shell}}{\frac{4}{3}\pi((2R)^3-R^3)}=\frac{-3Q}{28\piR^3}

B)

The electric field is E=\frac{1}{4\pi\epsilon_0}\frac{Qr}{R^3}

For 0 <r<R the electric field is zero, because the electric field inside the conductor is zero.

C)

For R <r <2R According to gauss law

E(4\pi r^2)=\frac{Q}{\epsilon_0}+\frac{4\pi\rho}{3\epsilon_0}(r^3-R^3)

substitute \rho=\frac{-3Q}{28\piR^3}

E=\frac{2}{7\pi\epsilon_0}\frac{Q}{r^2}-\frac{Qr}{28\piR^3}

D)

The net charge enclosed for each r in this range is positive and the electric field is outward

E)

For r>2R

Charge enclosed is zero, so electric field is zero

8 0
3 years ago
What are the steps to extract metal from the earths crust
Pani-rosa [81]
<span>Methods of extraction include: extract by electrolysis, extract by reaction with carbon or carbon monoxide, and extracted by various chemical reactions.</span>
4 0
3 years ago
What is electromagnetism​
antoniya [11.8K]
The interaction of electric currents or fields and magnetic fields.
4 0
3 years ago
Read 2 more answers
How does the physical structure of a plant have<br> Large leaves help it survive?
elena-14-01-66 [18.8K]

The large leaves help it survive as they serve as the<u> organ for photosynthesis.</u>

Explanation:

  • Photosynthesis, the process by which green plants and certain other organisms transform light energy into chemical energy.
  • During photosynthesis in green plants, light energy is captured and used to convert water, carbon dioxide, and minerals into oxygen and energy-rich organic compounds
  • Leaves provide food and air to help a plant stay healthy and grow. Through photosynthesis, leaves turn light energy into food.
  • Through pores, or stomata, leaves breathe in carbon dioxide and breathe out oxygen. Leaves also release excess water.
  • Most leaves are broad and so have a large surface area allowing them to absorb more light
  • A thin shape means a short distance for carbon dioxide to diffuse in and oxygen to diffuse out easily.
  • The exchange of oxygen and carbon dioxide in the leaf occurs through pores called stomata.
  • Normally stomata open when the light strikes the leaf in the morning and close during the night.

3 0
3 years ago
2.- Si una cámara fotográfica emite un pulso de sonido para enfocar un objeto, determinar
uranmaximum [27]

Answer:

a. El tiempo de recorrido es 5.882\times 10^{-3} segundos para un objeto localizado a un metro de distancia de la cámara fotográfica.

b. El tiempo de recorrido es 0.118 segundos para un objeto localizado a un metro de distancia de la cámara fotográfica.

Explanation:

El sonido es un tipo de onda mecánica, que es un tipo de onda que necesita de un medio material para propagarse. En este caso, entendemos que el sonido se propaga a través del aire atmosférico hasta llegar a su destino y devolverse a rapidez constante. Entonces, podemos estimar el tiempo (t), medido en segundos, a partir de la siguiente fórmula:

t = \frac{2\cdot x_{s}}{v_{s}}

Donde:

x_{s} - Distancia entre la cámara fotográfica y el objeto, medida en metros.

v_{s} - Rapidez del sonido en el aire atmosférico, medida en metros por segundo.

A continuación, calculamos el tiempo de recorrido:

a. (x_{s} = 1\,m, v_{s} = 340\,\frac{m}{s})

t = \frac{2\cdot (1\,m)}{340\,\frac{m}{s} }

t = 5.882\times 10^{-3}\,s

El tiempo de recorrido es 5.882\times 10^{-3} segundos para un objeto localizado a un metro de distancia de la cámara fotográfica.

b. (x_{s} = 20\,m, v_{s} = 340\,\frac{m}{s})

t = \frac{2\cdot (20\,m)}{340\,\frac{m}{s} }

t = 0.118\,s

El tiempo de recorrido es 0.118 segundos para un objeto localizado a un metro de distancia de la cámara fotográfica.

8 0
3 years ago
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