then solve for v
so
so v = (3m/s^2)(6s)
so v = 18m/s
When a hammer thrower releases her ball, she is aiming to maximize the distance from the starting ring. Assume she releases the
1 answer:
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then solve for v
so
so v = (3m/s^2)(6s)
so v = 18m/s
Answer:
i) 0.7
ii) 1.39
iii) 0.6
Next time, when compiling a Physics question, ensure you put the unit of each measurement.
Explanation:
i) T = time of flight =
where u = speed = 4, A = 60 and g = acceleration due to gravity = 10 (It is a constant);
Subsituting the values, we have: T = = 0.7
ii) distance travel = Range = R =
where u = speed = 4, A = 60 and g = acceleration due to gravity = 10 (It is a constant);
Subsituting values, we have: R = = 1.39
iii) Maximum Height = H =
where u = speed = 4, A = 60 and g = acceleration due to gravity = 10 (It is a constant);
Subsituting values, we have: = 0.6
Answer:
4.15 m/s
Explanation:
Its given that acceleration is 0.1 m/s² with a direction opposite to the velocity. Since, the direction of acceleration is opposite to the velocity, this gives us a hint that the velocity is decreasing and so acceleration would be negative.
i.e.
acceleration = a = - 0.1 m/s²
Distance covered = S = 6m
Velocity after covering 6 meters = Final velocity = = 4 m/s
We need to find the initial speed, which will be the same as the magnitude of initial velocity.
Initial velocity = = ?
3rd equation of motion relates the acceleration, distance, final velocity and initial velocity as:
Using the known values in the formula, we get:
Thus, the initial speed of the ball was 4.15 m/s