Answer:
A
Step-by-step explanation:
We can find the surface area of the object by adding the surface areas of each part. We have many rectangle faces to count and two triangular faces. Each has a formula for the area. We will find the area of each and then add them all together.
Triangle - 0.5 *b*h
Rectangle - b*h
<u>Triangles</u>
There are two triangles on either side. The height is 1.5. The base is 1.8.
0.5(1.5)(1.8)=1.35 meters squared
Since there are two, we will add 1.35+1.35 in our final calculation.
<u>Rectangles</u>
We will start by calculating the largest rectangle on the side. It has height of 4 and a base of 2.5 (shown above left).
4(2.5)=10
Since there are two (one we can see and one we can't), we will add 10+10 in our final calculation.
Next we calculate the top and bottom. The height is 3 and the base is 2.5 on top. But the bottom sticks out more and adds 1.8 to its base.
Top - 3(2.5)=7.5
Bottom-3(2.5+1.8)=12.9
Finally, we will calculate the front side and back(not visible) as well as the slant up front. The back side has height 4 and base 3. The front side has base 3 and height 4-1.5=2.5. The slant has base 2.3 and height 3.
Back - 4(3)=12
Front- 3(2.5)=7.5
Slant - 3(2.3)=6.9
We add all together for the total surface area: 1.35+1.35+10+10+7.5+12.9+12+7.5+6.9=69.5 meters squared.
Answer:
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We can use SOH, CAH and TOA, but first we must find the length of a hypotenuse:
h =
sin (theta)=
2/√13cos ( theta) =
-3/√13tan (theta) =
-2/3cot (theta ) =
-3/2sec (theta) = 1/cos(theta ) =
-√13/3csc(theta ) = 1/ sin (theta) =
√13/2
Answer:
x = 120-95
Step-by-step explanation:
The correct equation for the expression is:
∠AFC = ∠AFB+ ∠BFC
Given that
∠AFC = 120°
∠BFC = 95°
Substitute
120= ∠AFB+95
∠AFB = 120-95
If ∠AFB = x
The required equation will be:
x = 120-95
