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2 years ago

PLZZ I WILL GIVE Braliest!!!

Chemistry

2 answers:

Semenov [28]2 years ago

5 0

Answer:

my answer d.

Explanation:

sorry if not true

9966 [12]2 years ago

3 0

$\huge{\mathbb{\tt {QUESTION:}}}$

What makes a radioactive decay chain end?

OA. The final element has the longest half-life.

OB. All mass has been converted to energy.

OC. The radiation is absorbed by something.

OD. The final product is not radioactive.

$\huge{\mathbb{\tt {ANSWER:}}}$

D. The final product is not radioactive

 $\huge{\mathbb{\tt {EXPLANATION:}}}$ 

A radioactive decay chain will end when the last particle formed is stable. The initial radioactive isotope is called the parent isotope.

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Answer:

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Explanation:

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2 years ago

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3 years ago

What are 3 Properties of Convalent electrons

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Do not ionize in solutions
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2 years ago

What is the preasure in atmospheres of 20 mol of nitrogen gas in 36.2 L cylinder at 25 degrees C?

Savatey [412]

Answer:

P = 13.5 atm

Explanation:

Given that

No. of moles, n = 20 moles

Volume of nitrogen gas = 36.2 L

Temperature = 25°C = 298 K

We need to find the pressure of the gas. Using the ideal gas equation

PV = nRT

Where

R is gas constant, $R=0.082057\ L-atm/K-mol$

So,

$P=\dfrac{nRT}{V}\\\\P=\dfrac{20\times 0.082057\times 298}{36.2 }\\\\P=13.5\ atm$

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7 0

2 years ago

A ball is dropped from a height of 1.20 m and hits the floor. The ball compresses and then reforms to spring upwards from the fl

diamong [38]

Answer:

$\large \boxed{\text{98 m$\cdot$s}^{-2}}$

Explanation:

The formula for the velocity of the ball is

$v = \sqrt{2gh}$

1. Velocity at time of impact

$v = -\sqrt{2 \times 9.807 \times 1.20} = -\sqrt{23.54} = -\textbf{4.85 m/s}$

2. Velocity on rebound

The ball has enough upward velocity to reach a height of 0.86 m.

$v = \sqrt{2 \times 9.807 \times 0.86} = \sqrt{16.87} =\textbf{4.11 m/s}$

3. Acceleration

$a = \dfrac{\Delta v}{\Delta t} = \dfrac{4.11 - (-4.85)}{ 0.091} = \dfrac{8.96 }{0.091} =\textbf{98 m$\cdot$s}^{\mathbf{-2}}\\\\\text{The acceleration while the ball is in contact with the floor is $\large \boxed{\textbf{98 m$\cdot$s}^{\mathbf{-2}}}$}$

5 0

3 years ago