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2 years ago

PLZZ I WILL GIVE Braliest!!!

Chemistry

2 answers:

Semenov [28]2 years ago

5 0

Answer:

my answer d.

Explanation:

sorry if not true

9966 [12]2 years ago

3 0

$\huge{\mathbb{\tt {QUESTION:}}}$

What makes a radioactive decay chain end?

OA. The final element has the longest half-life.

OB. All mass has been converted to energy.

OC. The radiation is absorbed by something.

OD. The final product is not radioactive.

$\huge{\mathbb{\tt {ANSWER:}}}$

D. The final product is not radioactive

 $\huge{\mathbb{\tt {EXPLANATION:}}}$ 

A radioactive decay chain will end when the last particle formed is stable. The initial radioactive isotope is called the parent isotope.

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Which type of reaction is represented by the generic equation ab cd right arrow. ad cb? combustion decomposition single replacem

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The illustration would be that of a double replacement reaction.

<h3>What are double replacement reactions?</h3>

They are reactions in which 2 ionic compounds exchange ions to form two new products.

Thus, in the reaction: ab + cd ----------> ad + cb

ab and cd are two ionic compounds. The b in ab is replaced by the d in cd while the d in cd itself is replaced by the b in ab. Hence, new products, ad and cd, are formed.

More on double replacement reactions can be found here: brainly.com/question/19267538

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andrey2020 [161]

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2 years ago

The gas cyclobutane, C4H8(g), can be used in welding. When cyclobutane is burned in oxygen, the reaction is: C4H8(g) + 6 O2(g)4

Snowcat [4.5K]

Answer:

$\Delta H^o _{rxn} = -2568.9 \ kJ$

$H = 350 JK^{-1}$

$T_{max} = 32.4 ^o C$

Explanation:

From the question we are told that

The reaction of cyclobutane and oxygen is

$C_4H_8_{(g)} + 6 O_2_{(g)} \to 4 CO_2_{(g)} + 4 H_2O_{(g)}$

ΔH°f (kJ mol-1) : C4H8(g) = 27.7 ; CO2(g) = -393.5 ; H2O(g) = -241.8 ΔH° = kJ

Generally ΔH° for this reaction is mathematically represented as

$\Delta H^o _{rxn} = [[4 * \Delta H^o_f (CO_2_{(g)} ) + 4 * \Delta H^o_f(H_2O_{(g)} ] -[\Delta H^o_f (C_2H_6_{(g)} + 6 * \Delta H^o_f (O_2_{(g)}) ] ]$

=> $\Delta H^o _{rxn} = [[4 * (-393.5) + 4 * (-241.8) ] -[ 27.7 + 6 * 0]$

=> $\Delta H^o _{rxn} = -2568.9 \ kJ$

Generally the total heat capacity of 4 mol of CO2(g) and 4 mol of H2O(g), using CCO2(g) = 37.1 J K-1 mol-1 and CH2O(g) = 33.6 J K-1 mol-1. C = J K-1 is mathematically represented as

$H = [ 4 * C_{CO_2_{(g)}} + 6* C_{CH_2O_{(g)}}]$