What are the options? based on the volume it can differ but in general pipettes and graduated cylinder are the best. <span />
Answer:
"
" is the right answer.
Explanation:
Given:
Partial pressure of
,
= 0.20 atm
Partial pressure of
,
= 0.15 atm
at ![400^{\circ} C](https://tex.z-dn.net/?f=400%5E%7B%5Ccirc%7D%20C)
As we know,
⇒ ![K_p = \frac{pN_2\times pH_2^3}{pNH_3^2}](https://tex.z-dn.net/?f=K_p%20%3D%20%5Cfrac%7BpN_2%5Ctimes%20pH_2%5E3%7D%7BpNH_3%5E2%7D)
By putting the values, we get
![1.5\times 10^3=\frac{0.20\times (0.15)^3}{pNH_3^2}](https://tex.z-dn.net/?f=1.5%5Ctimes%2010%5E3%3D%5Cfrac%7B0.20%5Ctimes%20%280.15%29%5E3%7D%7BpNH_3%5E2%7D)
![pNH_3^2 = \frac{0.000675}{1.5\times 10^3}](https://tex.z-dn.net/?f=pNH_3%5E2%20%3D%20%5Cfrac%7B0.000675%7D%7B1.5%5Ctimes%2010%5E3%7D)
![=6.7\times 10^{-4} \ atm](https://tex.z-dn.net/?f=%3D6.7%5Ctimes%2010%5E%7B-4%7D%20%5C%20atm)
A weak bond between two molecules resulting from an electrostatic attraction between a proton in one molecule and an electronegative atom in another
Answer:
The force of the gases pushes downward at the same time that the gases push the rocket upwards. 1.
Explanation:
![KI (s) ----\ \textgreater \ K(s) + I_2 (g)](https://tex.z-dn.net/?f=KI%20%28s%29%20%20----%5C%20%5Ctextgreater%20%5C%20%20%20%20%20K%28s%29%20%20%2B%20I_2%20%28g%29)
Now, balance the equation:
![2KI (s) ----\ \textgreater \ 2K(s) + I_2 (g)](https://tex.z-dn.net/?f=2KI%20%28s%29%20%20----%5C%20%5Ctextgreater%20%5C%20%20%20%20%202K%28s%29%20%20%2B%20I_2%20%28g%29)
![I_2](https://tex.z-dn.net/?f=I_2%20)
in gaseous state exist as a diatomic molecule.