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valentina_108 [34]
4 years ago
10

Ions form when atoms gain or lose protons. True or False.

Chemistry
2 answers:
stiv31 [10]4 years ago
5 0

"Ions are formed when atoms lose or gain electrons in order to fulfill the octet rule and have full outer valence electron shells. When they lose electrons, they become positively charged and are named cations. When they gain electrons, they are negatively charged and are named anions." -Study.com

Fed [463]4 years ago
5 0

The answer is true. You could just look it up.

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How are elements in the nitrogen family ( group 15) similar to each other
Nina [5.8K]
They have similar electron configurations and have similar ionic chargers
4 0
3 years ago
Read 2 more answers
Uranus is much larger than Earth, with a surface area of 8.10 × 1015m2 with an atmosphere of low-density gases: 82.5% H2, 15.2%
sdas [7]

Answer:

mass of Uranus: 9.31x10^22 kg

Explanation:

As I stated in the comments, the question in this problem is to calculate the mass of Uranus, given it's conditions.

Now, we have the data of the atmosphere gases, but for calculations, this data is irrelevant.

To calculate the mass of Uranus, we can use the second law of Newton which is:

F = m * a (1)

In this case, the only Force exerting here would be the weight so:

F = m * g (2)

And the force of Uranus, can also be expressed in terms of pressure and Area so:

F = P * S (3)

Now, if we replace (3) in (2) we have:

P * S = m * g

Solving for m:

m = P * S / g (4)

We have all the data, therefore, let's replace it in the above expression to calculate the mass of Uranus:

m = 1x10^8 * 8.1x10^15 / 8.7

m = 9.31x10^22 kg

This is the mass of Uranus

8 0
4 years ago
If you prepare 525 mL of a .650M MgCl2 solution, how many grams of solute would you need?
myrzilka [38]

Answer:

Explanation:

525ml of 0.6550M MgCl₂ => 0.525L x 0.650M = 0.3413mole MgCl₂

0.3413mole MgCl₂ = 0.3413mole x 94 g/mole = 32.1g MgCl₂

4 0
3 years ago
Make the following conversions using dimensional analysis. SHOW YOUR WORK. Express your answers in scientific notation.
Natali5045456 [20]

(A) 14.8 g → 1.48 × 10^7 µg

The prefix µ means “× 10^(-6)”, so 1 µg = 1 × 10^(-6) g

The conversion factor (CF) = 1 µ g/1 × 10^(-6) g

∴ Mass = 14.8 g × [1 µg/1 × 10^(-6) g] = 1.48 × 10^7 µg

(B) 3.72 g → 3.72× 10^(-3) kg

The prefix k means “× 10^3”, so 1 kg = 1 × 10^3 g

CF = 1 kg/1 × 10^3 g

∴ Mass = 3.72 g × [1 kg/1 × 10^3 g] = 3.72× 10^(-3) kg

(C) 7.5 × 10^4 J →  75 kJ

CF = 1 kJ/1 × 10^3 J

∴ Energy = 7.5 × 10^4 J × [1 kJ/1 × 10^3 J] = 3.72× 10^(-3) kJ = 7.5 × 10^1 kJ

= 75 kJ

5 0
3 years ago
Explain how you would calculate the q for warming 100.0 grams of liquid water from 0°C to 100 °C.
mojhsa [17]

Answer:

mass = 100 g

T1 = 0°C

T2 = 100 °C

C = 1 cal/g°C

Q = mC(T2 -T1)

Q = 100(1)(100 - 0)

Q = 100(100)

Q = 10000 cal

Explanation:

6 0
3 years ago
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