1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
NeTakaya
3 years ago
11

A policeman in a stationary car measures the speed of approaching cars by means of an ultrasonic device that emits a sound with

a frequency of 41.2 khz. A car is approaching him at a speed of 33.0 m/s. The wave is reflected by the car and interferes with the emitted sound producing beats. What is the frequency of the beats? The speed of sound in air is 330 m/s.

Physics
2 answers:
beks73 [17]3 years ago
6 0

Answer:

4.6 kHz

Explanation:

The formula for the Doppler effect allows us to find the frequency of the reflected wave:

f'=(\frac{v}{v-v_s})f

where

f is the original frequency of the sound

v is the speed of sound

vs is the speed of the wave source

In this problem, we have

f = 41.2 kHz

v = 330 m/s

vs = 33.0 m/s

Therefore, if we substitute in the equation we find the frequency of the reflected wave:

f'=(\frac{330 m/s}{330 m/s-33.0 m/s})(41.2 kHz)=45.8 kHz

And the frequency of the beats is equal to the difference between the frequency of the reflected wave and the original frequency:

f_B = |f'-f|=|45.8 kHz-41.2 kHz|=4.6 kHz

lara [203]3 years ago
6 0

The frequency of the beats is about 9.2 kHz

\texttt{ }

<h3>Further explanation</h3>

Let's recall the Doppler Effect formula as follows:

\large {\boxed {f' = \frac{v + v_o}{v - v_s} f}}

<em>f' = observed frequency</em>

<em>f = actual frequency</em>

<em>v = speed of sound waves</em>

<em>v_o = velocity of the observer</em>

<em>v_s = velocity of the source</em>

<em>Let's tackle the problem!</em>

\texttt{ }

<u>Given:</u>

actual frequency = f = 41.2 kHz

velocity of the car = v_c = 33.0 m/s

speed of sound in air = v = 330 m/s

<u>Asked:</u>

frequency of the beats = Δf = ?

<u>Solution:</u>

<em>Firstly , we will use the formula of </em><em>Doppler Effect</em><em> as follows:</em>

f' = \frac{v + v_c}{v - v_c} \times f

f' = \frac{330 + 33}{330 - 33} \times 41.2

f' = \frac{363}{297} \times 41.2

f' = \frac{11}{9} \times 41.2

f' = 50 \frac{16}{45} \texttt{ kHz}

f' \approx 50.4 \texttt{ kHz}

\texttt{ }

<em>Next , we could calculate the frequency of the beats as follows:</em>

\Delta f = f' - f

\Delta f \approx 50.4 - 41.2

\Delta f \approx 9.2 \texttt{ kHz}

\texttt{ }

<h3>Conclusion:</h3>

The frequency of the beats is about 9.2 kHz

\texttt{ }

<h3>Learn more</h3>
  • Doppler Effect : brainly.com/question/3841958
  • Example of Doppler Effect : brainly.com/question/810552

\texttt{ }

<h3>Answer details</h3>

Grade: College

Subject: Physics

Chapter: Sound Waves

\texttt{ }

Keywords: Sound, Wave , Wavelength , Doppler , Effect , Policeman , Stationary , Frequency , Speed , Beats

You might be interested in
A hoop (I = MR2) of mass 3 kg and radius 1.1 m is rolling at a center-of-mass speed of 11 m/s. An external force does 842 J of w
Scilla [17]

Answer:

v_f = 20 m/s

Explanation:

Since the hoop is rolling on the floor so its total kinetic energy is given as

KE = \frac{1}{2}mv^2 + \frac{1}{2} I\omega^2

now for pure rolling condition we will have

v = R\omega

also we have

I = mR^2

now we will have

KE = \frac{1}{2}mv^2 + \frac{1}{2}(mR^2)\frac{v^2}{R^2}

KE = mv^2

now by work energy theorem we can say

W = KE_f - KE_i

842 J = mv_f^2 - mv_i^2

842 = 3(v_f^2) - 3\times 11^2

now solve for final speed

v_f = 20 m/s

3 0
3 years ago
A motorist makes a trip of 180 miles. For the first 90 mph she drives at a constant speed of 30 mph. What constant speed must sh
Likurg_2 [28]
I think it is 50 mhp because it's in half
5 0
3 years ago
A shopper pushes a 5.32 kg grocery cart with a 12.7 N force directed at -28.7° below horizontal. A friction force of 8.33 N push
atroni [7]

Answer:

0.8214 m/s^2

Explanation:

Fnet= Fpushed - Ffriction

Fpushed = 12.7N      Ffriction = 8.33N

Fnet = 12.7N - 8.33N = 4.37N

Fnet= mass(acceleration)

Fnet = 4.37N    mass = 5.32 kg

4.37N = 5.32 kg(acceleration)

acceleration= 0.8214 m/s^2

3 0
3 years ago
21) A youngster having a mass of 50.0 kg steps off a 1.00 m high platform. If she keeps her legs fairly rigid and comes to rest
zlopas [31]

Answer:

-22,150 N

Explanation:

When the youngster jumps off the platform, during the fall her initial potential energy is converted into kinetic energy, according to the law of conservation of energy. Therefore, we can write:

mgh=\frac{1}{2}mu^2

where the term on the left is the potential energy while the term on the right is the kinetic energy, and where

m = 50.0 kg is the mass of the youngster

g=9.8 m/s^2 is the acceleration due to gravity

h = 1.00 m is the heigth of the platform

u is the speed of the youngster as she reaches the floor

Solving for u,

u=\sqrt{2gh}=\sqrt{2(9.8)(1.00)}=4.43 m/s

Then, when the youngster hits the floor, the force exerted on her during the deceleration is given by:

F=\frac{\Delta p}{\Delta t}=\frac{m(v-u)}{\Delta t}

where \Delta p is her change in momentum, and where

m is the mass

v = 0 is the final velocity (she comes to a stop)

u = 4.43 m/s is the initial velocity

\Delta t=10.0 ms =0.010 s is the duration of the collision

Substituting,

F=\frac{(50.0)(0-4.43)}{0.010}=-22150 N

And the negative sign means the direction of the force is opposite to the motion (so, upward).

6 0
3 years ago
Vapor pressure is related to the temperature of the liquid. user: in an open system, the vapor pressure is equal to the _____. i
iVinArrow [24]

Answer

-Directly;  outside air pressure

Vapor pressure is directly related to the temperature of the liquid. user: in an open system, the vapor pressure is equal to the outside air pressure.

Explanation;

-As the temperature of a system increases, the average kinetic energy of the molecules increases in both the liquid and gas phases.

-A higher average kinetic energy facilitates the escape of molecules from the liquid phase into the gas phase. At the same time, the rate of return of gas phase molecules to the liquid also increases. A new equilibrium point is reached at a higher gaseous vapor pressure. The increase in vapor pressure with temperature is exponential.


6 0
3 years ago
Read 2 more answers
Other questions:
  • A 20. cm telescope collects how many times the light collected by a 5.0 cm telescope?
    8·1 answer
  • Isaac Newton’s investigations of gravity explained which truth?
    9·1 answer
  • If you were on a decision making board with the task of choosing which innovation to fund, what criteria would you use to make y
    11·1 answer
  • A 12 A fuse is placed in a parallel circuit that has two branches. 8 A flows in branch 1 and 6 A flows in branch 2. This fuse
    15·1 answer
  • How were the fossil symbols and mountain bets helpful in deciding where to move the continenets
    11·1 answer
  • Sound wave A has a lower frequency than sound wave B, but both waves
    5·2 answers
  • A 4-kg mass moving with speed 2 m/s, and a 2-kg mass moving with a speed of 4 m/s, are gliding over a horizontal frictionless su
    13·1 answer
  • The μ-receptor (mu) a. plays a role in analgesia and the rewarding effects of morphine. b. overlaps with the κ-receptor in its d
    11·1 answer
  • how does the charge of a particle affect the direction in wich the particles deflected in a megnetic field
    8·2 answers
  • What is an inclined plane? How does it make our work easier?
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!