1) Example of contact force: friction
2) Examples of non-contact forces: gravity and electromagnetic force
Explanation:
1)
Contact forces are forces that acts only when the objects involved are touching.
An example of contact force in the geosphere is friction. Friction is a force that acts when two objects slide past each other, and the surfaces of the two objects are in contact. Due to the presence of "microbumps" on the two surfaces, there is a resistive force opposing the motion of the two objects, and this force is called friction.
Friction also acts when an object is moving through a fluid, although it takes a different name: resistance. Also in this case, the resistance acts in the direction opposite to the motion of the object, slowing it down.
2)
Non-contact forces are forces that act from a distance, therefore they act even when the objects involved are not touching.
Examples of non-contact forces are:
- Gravitational force: this is an attractive force that acts between any object with mass. Its magnitude is directly proportional to the product of the masses of the two objects and inversely proportional to the square of the distance between the two objects.
- Electromagnetic force: this is a force exerted between electrically charged objects. Its magnitude is directly proportional to the product of the two charges and inversely proportional to the square of the distance between the charges. It can be attractive (if the charges have opposite sign) or repulsive (if the charges have same sign).
Learn more about forces:
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They got back in the Lunar Explorer Module
A material you are testing conducts electricity but cannot be pulled into wires. It is most likely a metalloid. Hope this helps!
Answer:
a₁ = 0.63 m/s² (East)
a₂ = -1.18 m/s² (West)
Explanation:
m₁ = 95 Kg
m₂ = 51 Kg
F = 60 N
a₁ = ?
a₂ = ?
To get the acceleration (magnitude and direction) of the man we apply
∑Fx = m*a (⇒)
F = m₁*a₁ ⇒ 60 N = 95 Kg*a₁
⇒ a₁ = (60N / 95Kg) = 0.63 m/s² (⇒) East
To get the acceleration (magnitude and direction) of the woman we apply
∑Fx = m*a (⇒)
F = -m₂*a₂ ⇒ 60 N = -51 Kg*a₂
⇒ a₂ = (60N / 51Kg) = -1.18 m/s² (West)
For every case we apply Newton’s 3
d Law
