To answer this question, first we take note that the maximum height that can be reached by an object thrown straight up at a certain speed is calculated through the equation,
Hmax = v²sin²θ/2g
where v is the velocity, θ is the angle (in this case, 90°) and g is the gravitational constant. Since all are known except for v, we can then solve for v whichi s the initial velocity of the projectile.
Once we have the value of v, we multiply this by the total time traveled by the projectile to solve for the value of the range (that is the total horizontal distance).
The motion of the inferior angle of the scapula in the superior and lateral direction is called upward rotation.
<h3>What are the possible motions of the scapula?</h3>
The scapula or the shoulder blade has about six different types of motion it undergoes.
The six ways of movement of the scapula are:
- protraction,
- retraction,
- elevation,
- depression,
- upward rotation, and
- downward rotation
When the inferior angle of the scapula moves in the superior and lateral direction, the motion is called upward rotation.
Learn more about scapula motion at: brainly.com/question/16868917
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