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Harman [31]
3 years ago
12

Which organisms in soil helps relieve element so they can be recycled

Chemistry
1 answer:
Rudiy273 years ago
3 0

Answer:

Bacteria are also involved in many processes that are indispensable for our life on Earth. Many of these processes have to do with the recycling (reuse) of chemical elements that have been here since the formation of the planet

Explanation:

I hope it will help you

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Which of the following correctly represents 148 million kilometers in scientific notation?
ryzh [129]
The answer is 1.48 x 10^8. This is because 148 million is represented as 148 000 000 and it takes 8 decimal places to make it 1.48. Hope this helps!
5 0
3 years ago
Can sum1 help me ????
xeze [42]

Answer:

The principle of superposition states that the oldest sedimentary rock units are at the bottom, and the youngest are at the top. Based on this, layer C is oldest, followed by B and A. hope that helps

Explanation:

A=top

B=middle

C=bottom

8 0
3 years ago
Does each phrase describe photosynthesis, cellular respiration, or both? Drag and drop the phrases into the correct locations.
arlik [135]

Answer:

Anabolic Reaction : Photosynthesis

Occurs in plant life : Both

a way to store energy : Both

Catabolic Reaction : Cellular Respiration

a way to release energy : Both

involves oxygen and carbon dioxide : oxygen releases by the process of photosynthesis. Oxygen is involved in areobic respiration and not in anarobic respiration.

5 0
3 years ago
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True [87]

Answer:

i think D

Explanation:

3 0
3 years ago
The copper(I) ion forms a chloride salt (CuCl) that has Ksp = 1.2 x 10-6. Copper(I) also forms a complex ion with Cl-:Cu+ (aq) +
Mnenie [13.5K]

Answer: (a) The solubility of CuCl in pure water is 1.1 \times 10^{-3} M.

(b) The solubility of CuCl in 0.1 M NaCl is 9.5 \times 10^{-3} M.

Explanation:

(a)  Chemical equation for the given reaction in pure water is as follows.

           CuCl(s) \rightarrow Cu^{+}(aq) + Cl^{-}(aq)

Initial:                         0            0

Change:                    +x           +x

Equilibm:                   x             x

K_{sp} = 1.2 \times 10^{-6}

And, equilibrium expression is as follows.

          K_{sp} = [Cu^{+}][Cl^{-}]

       1.2 \times 10^{-6} = x \times x

             x = 1.1 \times 10^{-3} M

Hence, the solubility of CuCl in pure water is 1.1 \times 10^{-3} M.

(b)  When NaCl is 0.1 M,

       CuCl(s) \rightarrow Cu^{+}(aq) + Cl^{-}(aq),  K_{sp} = 1.2 \times 10^{-6}

   Cu^{+}(aq) + 2Cl^{-}(aq) \rightleftharpoons CuCl_{2}(aq),  K = 8.7 \times 10^{4}

Net equation: CuCl(s) + Cl^{-}(aq) \rightarrow CuCl_{2}(aq)

               K' = K_{sp} \times K

                          = 0.1044

So for, CuCl(s) + Cl^{-}(aq) \rightarrow CuCl_{2}(aq)

Initial:                     0.1                 0

Change:                -x                   +x

Equilibm:            0.1 - x                x

Now, the equilibrium expression is as follows.

              K' = \frac{CuCl_{2}}{Cl^{-}}

         0.1044 = \frac{x}{0.1 - x}

              x = 9.5 \times 10^{-3} M

Therefore, the solubility of CuCl in 0.1 M NaCl is 9.5 \times 10^{-3} M.

7 0
3 years ago
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