Answer:
C- A proton has about the same mass as a neutron .
Explanation:
In an atom such as a carbon atom, the masses of the proton and neutrons are the same.
The mass of the electrons is very negligible.
- Protons are the positively charged particles in an atom
- Neutrons do not carry any charges
- Both protons and neutrons have similar masses.
- They contribute the bulk of the mass of the atom.
- The electrons carry negative charges and they have negligible masses.
The mass of protons and neutrons are similar.
Answer:
2H2O2→2H2O+O2
Explanation:
This reaction is of the spontaneous decomposition of hydrogen peroxide down into water and oxygen.
Add 2 molecules of hydrogen peroxide and 2 molecules of water. Since oxygen is naturally diatomic, the total number of atoms of each element is now the same on both sides of the equation so it is balanced.
2H2O2→2H2O+O2
Radioactive is the most penetrating nuclear radiation
F the solubility of a gas in water is 5.0g/L when the pressure of the gas above the water is 2.0 atm, what is the pressure of the gas above the water <span>when the solubility of the gas is 1.0 g/L</span>
Here's how to solve this one.
The formula for solubility is
<span>P1 / P2 = solubility1 / solubility2 </span>
P1=2*1/5= .4 atm
So the correct answer is 0.4 atm.
Answer:
643g of methane will there be in the room
Explanation:
To solve this question we must, as first, find the volume of methane after 1h = 3600s. With the volume we can find the moles of methane using PV = nRT -<em>Assuming STP-</em>. With the moles and the molar mass of methane (16g/mol) we can find the mass of methane gas after 1 hour as follows:
<em>Volume Methane:</em>
3600s * (0.25L / s) = 900L Methane
<em>Moles methane:</em>
PV = nRT; PV / RT = n
<em>Where P = 1atm at STP, V is volume = 900L; R is gas constant = 0.082atmL/molK; T is absolute temperature = 273.15K at sTP</em>
Replacing:
PV / RT = n
1atm*900L / 0.082atmL/molK*273.15 = n
n = 40.18mol methane
<em>Mass methane:</em>
40.18 moles * (16g/mol) =
<h3>643g of methane will there be in the room</h3>
