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ddd [48]
3 years ago
8

A car accelerates from rest at a constant rate of 8m/s^2. How fast is it going after 10s? How far has it gone after 10s? What is

its average velocity for the interval t = 0 to t = 10s?
Physics
1 answer:
natka813 [3]3 years ago
7 0

Answer:

velocity after 10s(v)=80m/s  ,distance traveled after 10s(S)=400m,  average velocity for time interval 0-10s =40m/s

Explanation:

using the equation of motion,

v=u+at

u=0 (the body starts from rest)

a=8m/s²

t=10s

v= 0+8*10

v=80m/s

distance traveled after 10s,

v²=u²+2as

80²=0²+(2*8*S)

6400 =16S

S= 6400/16

S=400m

average velocity = \frac{v+u}{2}

u= 0, v =80m/s

average velocity = (80+0)/2

                          =40m/s

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if the pressure on a gas increases, the volume of the gas also increases is that statement true or false?
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Two wires A and B with circular cross-section are made of the same metal and have equal lengths, but the resistance of wire A is
Nesterboy [21]

Answer:

r₁/r₂ = 1/2 = 0.5

Explanation:

The resistance of a wire is given by the following formula:

R = ρL/A

where,

R = Resistance of wire

ρ = resistivity of the material of wire

L = Length of wire

A = Cross-sectional area of wire = πr²

r = radius of wire

Therefore,

R = ρL/πr²

<u>FOR WIRE A</u>:

R₁ = ρ₁L₁/πr₁²   -------- equation 1

<u>FOR WIRE B</u>:

R₂ = ρ₂L₂/πr₂²   -------- equation 2

It is given that resistance of wire A is four times greater than the resistance of wire B.

R₁ = 4 R₂

using values from equation 1 and equation 2:

ρ₁L₁/πr₁² = 4ρ₂L₂/πr₂²

since, the material and length of both wires are same.

ρ₁ = ρ₂ = ρ

L₁ = L₂ = L

Therefore,

ρL/πr₁² = 4ρL/πr₂²

1/r₁² = 4/r₂²

r₁²/r₂² = 1/4

taking square root on both sides:

<u>r₁/r₂ = 1/2 = 0.5</u>

6 0
4 years ago
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