Question

A car accelerates from rest at a constant rate of 8m/s^2. How fast is it going after 10s? How far has it gone after 10s? What is its average velocity for the interval t = 0 to t = 10s?

Answer 1

Answer:

velocity after 10s(v)=80m/s  ,distance traveled after 10s(S)=400m,  average velocity for time interval 0-10s =40m/s

Explanation:

using the equation of motion,

v=u+at

u=0 (the body starts from rest)

a=8m/s²

t=10s

v= 0+8*10

v=80m/s

distance traveled after 10s,

v²=u²+2as

80²=0²+(2*8*S)

6400 =16S

S= 6400/16

S=400m

average velocity = $\frac{v+u}{2}$

u= 0, v =80m/s

average velocity = (80+0)/2

                          =40m/s