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ddd [48]
3 years ago
8

A car accelerates from rest at a constant rate of 8m/s^2. How fast is it going after 10s? How far has it gone after 10s? What is

its average velocity for the interval t = 0 to t = 10s?
Physics
1 answer:
natka813 [3]3 years ago
7 0

Answer:

velocity after 10s(v)=80m/s  ,distance traveled after 10s(S)=400m,  average velocity for time interval 0-10s =40m/s

Explanation:

using the equation of motion,

v=u+at

u=0 (the body starts from rest)

a=8m/s²

t=10s

v= 0+8*10

v=80m/s

distance traveled after 10s,

v²=u²+2as

80²=0²+(2*8*S)

6400 =16S

S= 6400/16

S=400m

average velocity = \frac{v+u}{2}

u= 0, v =80m/s

average velocity = (80+0)/2

                          =40m/s

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We have that the sea level pressure for Leh area is 1150mb mathematically given as

Ps= 1150 mb

<h3> Sea level pressure</h3>

Question Parameters:

Ladakh is 800 mb.

<u>assuming </u>that Leh is at an altitude of 3500 m and every 100 m

increase in height with respect to sea level corresponds to 10 mb pressure,

Generally, for 3500m the pressure change will be 350 mb.

Therefore,  here for the sea level <em>pressure</em> we need to add,

Ps=800+350

Ps= 1150 mb

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2 years ago
A person carries a plank of wood 1.6 m long with one hand pushing down on it at one end with a force F1 and the other hand holdi
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Answer: 115.52\ N

Explanation:

Given

Length of plank is 1.6 m

Force F_1 is applied on the left side of plank

Force F_2 is applied 43 cm from the left end O.

Mass of the plank is m=13.7\ kg

for equilibrium

Net torque must be zero. Taking torque about left side of the plank

\Rightarrow mg\times 0.8-F_2\times 0.43=0\\\\\Rightarrow F_2=\dfrac{13.7\times 9.8\times 0.8}{0.43}\\\\\Rightarrow F_2=249.78\ N

Net vertical force must be zero on the plank

\Rightarrow F_1+W-F_2=0\\\Rightarrow F_1=F_2-W\\\Rightarrow F_1=249.78-13.7\times 9.8\\\Rightarrow F_1=115.52\ N

8 0
2 years ago
¿Cuál es la magnitud y dirección de la aceleración de los cuerpos en caída libre en el planeta Tierra?
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La magnitud es de 9.8 m/s² ... la aceleración de la gravedad en o cerca de la superficie de la Tierra.

La dirección es hacia el centro de la Tierra. (Llamamos a esa dirección "abajo").

6 0
3 years ago
Resisting force is
Alina [70]

Answer:

D

Explanation:

6 0
3 years ago
a tank circuit contains a capacitor and an inductor that produce 30 of reactance at the resonant frequency. the inductor has a q
Romashka-Z-Leto [24]

The total circuit current at the resonant frequency is 0.61 amps

What is a LC Circuit?

  • A capacitor and an inductor, denoted by the letters "C" and "L," respectively, make up an LC circuit, also referred to as a tank circuit, a tuned circuit, or a resonant circuit.
  • These circuits are used to create signals at particular frequencies or to receive signals from more complicated signals at particular frequencies.

Q =15 = (wL)/R

wL = 30 ohms = Xl

R = 2 ohms

Zs = R + jXl = 2 +j30 ohms where Zs is the series LR impedance

| Zs | = 30.07 <86.2° ohms

Xc = 1/(wC) = 30 ohms

The impedance of the LC circuit is found from:

Zp = (Zs)(-jXc)/( Zs -jXc)

Zp = (2+j30)(-j30)/(2 + j30-j30) = (900 -j60)2 = 450 -j30 = 451 < -3.81°

I capacitor = 277/-j30 = j9.23 amps

I Zs = 277/(2 +j30) = (554 - j8,310)/904 = 0.61 - j9.19 amps

I net = I cap + I Zs = 0.61 + j0.04 amps = 0.61 < 3.75° amps

Hence, the total circuit current at the resonant frequency is 0.61 amps

To learn more about LC Circuit from the given link

brainly.com/question/29383434

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5 0
1 year ago
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