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ddd [48]
3 years ago
8

A car accelerates from rest at a constant rate of 8m/s^2. How fast is it going after 10s? How far has it gone after 10s? What is

its average velocity for the interval t = 0 to t = 10s?
Physics
1 answer:
natka813 [3]3 years ago
7 0

Answer:

velocity after 10s(v)=80m/s  ,distance traveled after 10s(S)=400m,  average velocity for time interval 0-10s =40m/s

Explanation:

using the equation of motion,

v=u+at

u=0 (the body starts from rest)

a=8m/s²

t=10s

v= 0+8*10

v=80m/s

distance traveled after 10s,

v²=u²+2as

80²=0²+(2*8*S)

6400 =16S

S= 6400/16

S=400m

average velocity = \frac{v+u}{2}

u= 0, v =80m/s

average velocity = (80+0)/2

                          =40m/s

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Answer: 1.8\°

Explanation:

The diffraction angles \theta_{n} when we have a slit divided into n parts are obtained by the following equation:

dsin\theta_{n}=n\lambda (1)

Where:

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\lambda=540 nm=540(10)^{-9}m is the wavelength of the light  

n is an integer different from zero.

Now, the second-order diffraction angle is given when n=2, hence equation (1) becomes:

dsin\theta_{2}=2\lambda (2)

Now we have to find the value of \theta_{2}:

sin\theta_{2}=\frac{2\lambda}{d} (3)

Then:

\theta_{2}=arcsin(\frac{2\lambda}{d})   (4)

\theta_{2}=arcsin(\frac{2(540(10)^{-9}m)}{3.4(10)^{-5}m})   (5)

Finally:

\theta_{2}=1.8\°   (6)

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3 years ago
A certain car can accelerate from 0 to 60 mph in 7.9 s. What is the car's average acceleration in mph/s?
Anna007 [38]

Answer:

<em>a = 7.6\ mph/s</em>

Explanation:

<u>Motion With Constant Acceleration </u>

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The equation that describes the change of velocities is:

v_f=v_o+at

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vf  = final speed

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\displaystyle a=\frac{v_f-v_o}{t}

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Answer:

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