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3 years ago

Which of these is an environmental effect of building dams?

Chemistry

2 answers:

Dovator [93]3 years ago

8 0

The answer to the question is either B or D.

nadezda [96]3 years ago

7 0

Hmm... I'm unsure but its either B or D.

You might be interested in

How can you tell what is what and how that what affects what

VLD [36.1K]

Answer:

Hi, this is a super vague question, so its pretty confusing to answer. Could you please be a bit more specific?

If you are referring to chemistry, then how you tell "what is what" is by the molecular makeup of an element (Periodic table), and "how that..affects what", chemical reactions can occur between elements

8 0

3 years ago

Read 2 more answers

Periodic table, chemistry questions

ehidna [41]

Answer:

Explanation:

The Lanthanides were first discovered in 1787 when a unusual black mineral was found in Ytterby, Sweden. This mineral, now known as Gadolinite, was later separated into the various Lanthanide elements. In 1794, Professor Gadolin obtained yttria, an impure form of yttrium oxide, from the mineral.

7 0

3 years ago

At the equilibrium point in the decomposition of phosphorus pentachloride to chlorine and phosphorus trichloride, the following

Hitman42 [59]

Answer: $K_{eq}$ for the reaction is 5.55

Explanation:

Equilibrium constant is the ratio of the concentration of products to the concentration of reactants each term raised to its stochiometric coefficients.

The given balanced equilibrium reaction is,

$PCl_5(g)\rightleftharpoons PCl_3(g)+Cl_2(g)$

At eqm. conc. (0.010) M (0.15) M (0.37) M

The expression for equilibrium constant for this reaction will be,

$K_c=\frac{[Cl_2]\times [PCl_3]}{[PCl_5]}$

Now put all the given values in this expression, we get :

$K_c=\frac{(0.37)\times (0.15)}{(0.010)}$

$K_c=5.55$

Thus the $K_{eq}$ for the reaction is 5.55

5 0

3 years ago

CO(g)+2H2(g)⇌CH3OH(g) A reaction mixture in a 5.23-L flask at a certain temperature initially contains 27.2 g CO and 2.36 g H2.

irga5000 [103]

Answer: 5.70M

Explanation:

Molar mass of CO = 28.01 g/mol

Molar mass of H2 = 2.02 g/mol

Molar mass of CH3OH = 32.05 g/mol.

To determine the amount of each compound in the reaction mixture we use the formula.

Amount in mol = reacting mass/molar mass.

Inputing the given values we have,

26.6 g CO x (1 mol / 28.01 g ) = 0.9496608354 mol of CO.

To calculate the concentration of CO we use C=n/v, where n=amount and v= volume of CO.

Inputing the values in the formula

[CO] = 0.9496608354 mol CO / 5.23 L = 0.18158 M CO

Repeating thesame procedure for H

Amount of H=2.36 g H2 x ( 1 mol / 2.02 g ) = 1.168316832 mol of H2

Concentration of H2 in the mixture

[H2] = 1.168316832 mol H2 / 5.23 L = 0.223388 M of H2

Amount of CH3OH is determine similarly using rmass/molar mass

8.66 CH3OH x (1 mol / 32.05 g ) = 0.2702028081 mol of CH3OH

Concentration of

[CH3OH] = 0.2702028081 mol CH3OH/ 5.23 L = 0.051664 M CH3OH

Now equilibrium constant is determined by

Kc = [CH3OH] / [CO] [H2]^2

=0.051664/0.18158×0.223388×0.223388.

=5.70

7 0

3 years ago

9.00 g/h to kilograms per minute

Mkey [24]

9.00g/1hr * 1kg/100g * 1hr/60min = 0.00015kg/min or 1.5 * 10^-4kg/min.

4 0

3 years ago