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Wewaii [24]
2 years ago
8

A gas sample at 40° C occupies a volume of 3.22 L. If the temperature is raised to 55°C, what will the volume be, assuming the p

ressure remains constant?
Chemistry
1 answer:
Ksju [112]2 years ago
4 0

Answer:

3.374L

Explanation:

According to Charle's Law:

V1/T1=V2/T2 (At constant pressure and moles)

where V=Volume and T=Temperature.

The temperature must be in kelvin.

K=C°+273

T1=40+273=313K

T2=55+273=328K

By applying the formula, we get:

3.22/313=V2/328

V2=(3.22*328)/313

V2=3.374L

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Explain why bond angle of H2O is greater than OF2
atroni [7]
It's only a small difference (103 degrees versus 104 degrees in water), and I believe the usual rationalization is that since F is more electronegative than H, the electrons in the O-F bond spend more time away from the O (and close to the F) than the electrons in the O-H bond. That shifts the effective center of the repulsive force between the bonding pairs away from the O, and hence away from each other. So the repulsion between the bonding pairs is slightly less, while the repulsion between the lone pairs on the O is the same -- the result is the angle between the bonds is a little less.

Hope this helps!
7 0
3 years ago
What gets oxidized in a galvanic cell made with magnesium and zinc electrodes?
ankoles [38]

Answer: Magnesium

Explanation:

Galvanic cell is a device which is used for the conversion of the chemical energy produces in a redox reaction into the electrical energy.

The standard reduction potential for magnesium and zinc are as follows:

E^0_{[Mg^{2+}/Mg]}= -2.37V

E^0_{[Zn^{2+}/Zn]}=-0.76V

Reduction takes place easily if the standard reduction potential is higher (positive) and oxidation takes place easily if the standard reduction potential is less (more negative).

Here Mg undergoes oxidation by loss of electrons, thus act as anode. Zinc undergoes reduction by gain of electrons and thus act as cathode.

Mg\rightarrow Mg^{2+}+2e^-

Zn^{2+}+2e^-\rightarrow Zn

Thus magnesium gets oxidized.

4 0
3 years ago
Read 2 more answers
A gas mixture contains twice as many moles of o2 as n2. addition of 0.200 mol of argon to this mixture increases the pressure fr
pantera1 [17]
Number of moles of oxygen = x

number of moles of nitrogen = y

x = 2y

initial pressure, p1 = 0.8 atm

final pressure, p2 = 1.10 atm

At constant volume and temperature p1 / n1 = p2 / n2

=> p1 / p2 = n1 / n2

n1 = x + y = 2y + y = 3y

n2 = 0.2 + 3y

=> p1 / p2 = 3y / (0.2 + 3y)

=> 0.8 / 1.10 = 3y / (0.2 + 3y)

=> 0.8 (0.2 + 3y) = 1.10 (3y)

0.16 + 2.4y = 3.3y

=> 3.3y - 2.4y = 0.16

=> 0.9y = 0.16

=> y = 0.16 / 0.9

=. x = 2*0.16/0.9 = 0.356

Answer: 0.356 moles O2
8 0
3 years ago
The ___ is the number of protons in the nucleus of an atom of an element.<br> Fill in the blank.
Maurinko [17]
The atomic number is the number of protons in the nucleus
8 0
2 years ago
describe the general trend in electronegativity as metals in group 2 on the periodic table are concidered in order of increasing
hjlf

Answer:

Electronegativity decrease in group from top to bottom

Explanation:

6 0
3 years ago
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