Answer:
Let f be force of friction on the blocks kept on inclined plane. T be tension in the string
For motion of block on the inclined plane in upward direction
T - m₁gsin40 - f = m₁a
f = μ m₁gcos40
For motion of hanging block on in downward direction
m₂g - T = m₂ a
Adding to cancel T
m₂g - - m₁gsin40 - μ m₁gcos40 = a ( m₁+m₂ )
a = g (m₂ - - m₁sin40 - μ m₁cos40) / ( m₁+m₂ )
Putting the values
a = 9.8 ( 4.75 - 2.12-1.045) / 7.6
2.04 m s⁻²
M₂ will go down and M₁ will go up with acceleration .
Explanation:
When you keep raisin in water and the raisin gets puffed.
Movement of salt-water in animal cell across our cell membrane.
To solve this exercise it is necessary to apply the concepts related to Robert Boyle's law where:

Where,
P = Pressure
V = Volume
T = Temperature
n = amount of substance
R = Ideal gas constant
We start by calculating the volume of inhaled O_2 for it:


Our values are given as
P = 1atm
T=293K 
Using the equation to find n, we have:




Number of molecules would be found through Avogadro number, then

