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4 years ago

5

Welding, cutting, or heating in any enclosed spaces involving which of the following metals should be performed with local exhau

st ventilation or employees should be provided air line respirators:

1 answer:

sweet [91]4 years ago

4 0

steal aluminum iron

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If you see something not being right on a project you are working-even if it isn't you doing the wrong thing-it is your ethical

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Answer:

Is this a "true or false" question?

Explanation:

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3 years ago

Read 2 more answers

Two blocks are connected by a string over a pulley. The hanging block has a mass of 8-kg and the one on the plane has a mass of

jeka94

Answer:

Let f be force of friction on the blocks kept on inclined plane. T be tension in the string

For motion of block on the inclined plane in upward direction

T - m₁gsin40 - f = m₁a

f = μ m₁gcos40

For motion of hanging block on in downward direction

m₂g - T = m₂ a

Adding to cancel T

m₂g - - m₁gsin40 - μ m₁gcos40 = a ( m₁+m₂ )

a = g (m₂ - - m₁sin40 - μ m₁cos40) / ( m₁+m₂ )

Putting the values

a = 9.8 ( 4.75 - 2.12-1.045) / 7.6

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M₂ will go down and M₁ will go up with acceleration .

Explanation:

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3 years ago

State two (2) examples of osmosis occurring in everyday life

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When you keep raisin in water and the raisin gets puffed.
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3 years ago

Observe yourself breathing and count the number of times you inhale per second. During each breath you probably inhale 0.66 L of

Pavel [41]

To solve this exercise it is necessary to apply the concepts related to Robert Boyle's law where:

$PV=nRT$

Where,

P = Pressure

V = Volume

T = Temperature

n = amount of substance

R = Ideal gas constant

We start by calculating the volume of inhaled O_2 for it:

$V = 21\% * 0.66L$

$V = 0.1386L$

Our values are given as

P = 1atm

T=293K $R = 0.083145kJ*mol^{-1}K^{-1}$

Using the equation to find n, we have:

$PV=nRT$

$n = \frac{PV}{RT}$

$n = \frac{(1)(0.1386)}{(0.0821)(293)}$

$n = 5.761*10^{-3}mol$

Number of molecules would be found through Avogadro number, then

$\#Molecules = 5.761*10^{-3}*6.022*10^{23}$

$\#Molecules = 3.469*10^{21} molecules$

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