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3 years ago

A student drops an object out the window of the top floor of a high-rise dormitory.

1 answer:

3 0

-- The acceleration due to gravity is 32.2 ft/sec² . That means that the
speed of a falling object increases by an additional 32.2 ft/sec every second.

-- If dropped from "rest" (zero initial speed), then after falling for 4 seconds,
the object's speed is (4.0) x (32.2) = 128.8 ft/sec.

-- 128.8 ft/sec = 87.8 miles per hour

Now we can switch over to the metric system, where the acceleration
due to gravity is typically rounded to 9.8 meters/sec² .

-- Distance = (1/2) x (acceleration) x (time)²

D = (1/2) (9.8) x (4)² = 78.4 meters

-- At 32 floors per 100 meters, 78.4 meters = dropped from the 25th floor.

The 5 points are certainly appreciated, but I do wish they were Celsius points.

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A truck is speeding up as it travels on an interstate. The truck's momentum (in kg · m/s) is proportional to the truck's speed (

muminat

Answer:

At the moment, the truck's momentum (in kg · m/s) is 2200 times as large as the truck's speed (in m/s).

This means that as the truck travels, the truck's momentum (in kg · m/s) is always 2200 times as large as the truck's speed (in m/s).

If the truck is travelling at 16 m/s, the truck's momentum is 35200 kg · m/s.

Explanation:

From the question,

The truck's momentum (in kg · m/s) is proportional to the truck's speed (in m/s).

Let the truck's momentum be P and the truck's speed be v,

Then we can write that

P∝v

Then,

P = kv

Where k is the proportionality constant

From the question,

At some moment the truck's momentum is 50600 kg · m/s and the truck's speed is 23 m/s,

To determine how many times the truck's speed is as large as the truck's momentum at this moment, we will divide the truck's momentum by the speed, that is

50600 ÷ 23 = 2200

Hence, at the moment, the truck's momentum (in kg · m/s) is 2200 times as large as the truck's speed (in m/s).

Since, dividing the truck's momentum by the truck's speed gives the proportionality constant k (that is, P/v = k), then

This means that as the truck travels, the truck's momentum (in kg · m/s) is always 2200 times as large as the truck's speed (in m/s).

From

P = kv

Then, k = P/v

At a moment, P = 50600 kg · m/s and v = 23 m/s

∴ k = 50600 kg · m/s ÷ 23 m/s = 2200 kg

k = 2200 kg

To determine the truck's momentum if the truck is traveling at 16 m/s

From

P = kv

k = 2200 kg

v = 16 m/s

∴ P = 2200 kg × 16 m/s

P = 35200 kg · m/s

Hence, if the truck is travelling at 16 m/s, the truck's momentum is 35200 kg · m/s.

3 0

3 years ago

At t1 = 2.00 s, the acceleration of a particle in counterclockwise circular motion is 6.00 i + 4.00 j m/s2 . It moves at constan

Jet001 [13]

The particle moves with constant speed in a circular path, so its acceleration vector always points toward the circle's center.

At time $t_1$ , the acceleration vector has direction $\theta_1$ such that

$\tan\theta_1=\dfrac{4.00}{6.00}\implies\theta_1=33.7^\circ$

which indicates the particle is situated at a point on the lower left half of the circle, while at time $t_2$ the acceleration has direction $\theta_2$ such that

$\tan\theta_2=\dfrac{-6.00}{4.00}\implies\theta_2=-56.3^\circ$

which indicates the particle lies on the upper left half of the circle.

Notice that $\theta_1-\theta_2=90^\circ$ . That is, the measure of the major arc between the particle's positions at $t_1$ and $t_2$ is 270 degrees, which means that $t_2-t_1$ is the time it takes for the particle to traverse 3/4 of the circular path, or 3/4 its period.

Recall that

$\|\vec a_{\rm rad}\|=\dfrac{4\pi^2R}{T^2}$

where $R$ is the radius of the circle and $T$ is the period. We have

$t_2-t_1=(5.00-2.00)\,\mathrm s=3.00\,\mathrm s\implies T=\dfrac{3.00\,\rm s}{\frac34}=4.00\,\mathrm s$

and the magnitude of the particle's acceleration toward the center of the circle is

$\|\vec a_{\rm rad}\|=\sqrt{\left(6.00\dfrac{\rm m}{\mathrm s^2}\right)^2+\left(4.00\dfrac{\rm m}{\mathrm s^2}\right)^2}=7.21\dfrac{\rm m}{\mathrm s^2}$

So we find that the path has a radius $R$ of

$7.21\dfrac{\rm m}{\mathrm s^2}=\dfrac{4\pi^2R}{(4.00\,\mathrm s)^2}\implies\boxed{R=2.92\,\mathrm m}$

8 0

3 years ago

A device used to measure electric current is called a ohmmeter. true or false

Semenov [28]

True
I hope this helps!!!

4 0

3 years ago

Read 2 more answers

How will sunlight most likely affect a black shirt on a hot summer day? the temperature of the shirt will depend on how much sun

vladimir2022 [97]

The correct answer is option (C) the temperature of the shirt will increase because all wavelengths of light are absorbed by the shirt.

The relationship of heat and light

Heat is a measure of the movement of particles in the body, the more particles move, the warmer the body becomes.
When the body absorbs light radiation, its particles vibrate in accordance with the electromagnetic radiation's wavelengths, which causes an increase in the temperature with the increase in particle movement.
The more wavelengths of radiation absorbed by an object, produces more heat.

Learn more about the Wavelength of light with the help of the given link:

brainly.com/question/13961990

#SPJ4

5 0

1 year ago

A massless string connects a 10.00 kg mass to a 13.00 kg cart which is resting on a frictionless horizontal surface. The mass ha

ch4aika [34]

The cart's acceleration to the right after the mass is released is determined as 7.54 m/s².

<h3>Acceleration of the cart</h3>

The acceleration of the cart is determined from the net force acting on the mass-cart system.

Upward force = Downward force

ma = mg

13a = 10(9.8)

13a = 98

a = 98/13

a = 7.54 m/s²

Thus, the cart's acceleration to the right after the mass is released is determined as 7.54 m/s².

Learn more about acceleration here: brainly.com/question/14344386

#SPJ1

6 0

2 years ago