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ludmilkaskok [199]
3 years ago
9

I need help with this ASAP!!!

Chemistry
2 answers:
RideAnS [48]3 years ago
7 0
You need help with what?
lisabon 2012 [21]3 years ago
3 0
A is 1
B is 1
C is 1/1836
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A sample of As weighs 73.2 grams. Will a sample of Kr that contains the same number of atoms weigh more or less than 73.2 grams?
My name is Ann [436]

Answer:

This means a sample of 73.2 grams As atoms weighs less than the same amount of Kr atoms

Explanation:

Step 1: Data given

Mass of As = 73.2 grams

Molar mass As = 74.92 g/mol

Molar mass of Kr = 83.80 g/mol

Step 2: Calculate moles As

Moles As = Mass As / molar mass As

Moles As = 73.2 grams . 74.92 g/mol

Moles As = 0.977 moles

Step 3: Calculate As atoms

As atoms = moles As * number of Avogadro

As atoms = 0.977 moles * 6.02 * 10^23

As atoms = 5.88 *10^23 As atoms

Step 4: Calculate moles Kr

Moles Kr = Atoms Kr / number of Avogadro

Moles Kr = 5.88 * 10^23 Kr atoms / 6.02 *10^23

Moles Kr = 0.977 moles

Step 5: Calculate mass Kr

Mass Kr = moles Kr * molar mass Kr

Mass Kr = 0.977 moles * 83.80 g/mol

Mass Kr = 81.9 grams

This means a sample of 73.2 grams As atoms weighs less than the same amount of Kr atoms

8 0
3 years ago
Which of the following will dissociate into the largest number of ions in solution?
Svetlanka [38]

Answer:D

Explanation:

4 0
3 years ago
During photosynthesis plants take in light energy from the sun carbon dioxide from the air and water to the roots which of the f
Genrish500 [490]

Glucose sugar and oxygen

5 0
3 years ago
Read 2 more answers
What molarity is prepared when a solution contains 0.277 moles of calcium bromide in 500 mL of solution (must change mL to Liter
Vladimir79 [104]

Answer:

0.554M of Calcium Bromide

Explanation:

Molarity by defintion is #of moles of something/litres of solution.

Therefore, here, we have 0.277 moles of calcium bromide and 500mL (divide 500ml by 1000 to go from mL to L because for every 1L there's 1000mL) or 0.5L.

Molarity= 0.277/0.5 = 0.554M of Calcium Bromide

5 0
3 years ago
3.0 cm x 4.0 cm x 1.0 cm<br><br>[?]cm^3​
CaHeK987 [17]

Explanation:

<em>Hi</em><em> </em><em>there</em><em>!</em><em>!</em>

<em>you</em><em> </em><em>asked</em><em> </em><em>to</em><em> </em><em>multiply</em><em> </em><em>these</em><em> </em><em>all</em><em> </em><em>right</em><em>,</em>

<em>you</em><em> </em><em>can</em><em> </em><em>simply</em><em> </em><em>multiply</em><em> </em><em>it</em><em> </em><em>,</em>

<em>=</em><em>3</em><em>cm</em><em> </em><em>×</em><em> </em><em>4</em><em> </em><em>cm</em><em> </em><em>×</em><em> </em><em>1</em><em>cm</em>

<em>=</em><em> </em><em>1</em><em>2</em><em>cm</em><em>^</em><em>2</em><em>×</em><em>1</em><em>cm</em><em> </em><em> </em><em> </em><em> </em><em>(</em><em>4</em><em>×</em><em>3</em><em>=</em><em>1</em><em>2</em><em>)</em>

<em>=</em><em> </em><em>1</em><em>2</em><em>cm</em><em>^</em><em>3</em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>(</em><em>1</em><em>2</em><em>×</em><em>1</em><em>=</em><em>1</em><em>2</em><em>)</em>

<em>Therefore</em><em>, </em><em> </em><em>the</em><em>answer is</em><em> </em><em>1</em><em>2</em><em> </em><em>cm</em><em>^</em><em>3</em><em>.</em>

<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em>

4 0
3 years ago
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