Alkali metals impart characteristic colours to the flame due to low ionisation enthalpy, when an alkali metal or its salt is heated in a flame, the valence electrons are excited to higher energy level.
A monkey needs to use more force and strength than a bat when swinging and they can get more momentum to push forward. and bat needs shorter limbs so they don’t have much weight to carry when they are flapping their wings. they will go faster with less mass in their arms.
Answer:
241 J/kg K.
Explanation:
From the complete question, the mass of the sample= 0.37 kg, Final temperature of the sample =14.5°C (287.5K), the Initial temperature of the sample = -1.2°C(271.8 K).
Therefore, the Change in temperature,∆T = final temperature of the sample - initial temperature of the sample.
Hence, ∆T= 287.5 - 271.8.
∆T= 15.7 K.
Using the formula below;
Q= MC∆T-----------------------------------(1).
Where M= mass of the sample= 0.37 kg, Q = the heat required to raise the temperature and C= specific heat capacity= 1.4 kJ= 1.4 × 1000 = 1,400 J.
Slotting in the values into equation (1) above, we have;
1400= 0.37 × C × 15.7K
1400= 5.809C.
C= 241.005336546737820.
Specific heat capacity,C;
= 241 J/kg K.
The chemist will report the specific heat capacity of the substance as 241 J/kg K.
Answer:
Enthalpy change = -44.12 kJ
Explanation:
<u>Given: </u>
ΔH°f(C2H6O(l)) = -277.69 kj/mol
ΔH°f(C2H4(g)) = 52.26 kj/mol
ΔH°f(H2O) = -285.83 kj/mol
<u>To determine:</u>
Enthalpy change for the formation of C2H6O
<u>Calculation:</u>
The given reaction is:
The enthalpy change for the reaction is given as;
where n(products) and n(reactants) are the moles of products and reactants
Substituting the appropriate values for n and ΔH°f:
![\Delta H = 1\Delta H^{0}f(C2H6O)-[1\Delta H^{0}f(C2H4)+1\Delta H^{0}f(H2O)]](https://tex.z-dn.net/?f=%5CDelta%20H%20%3D%201%5CDelta%20H%5E%7B0%7Df%28C2H6O%29-%5B1%5CDelta%20H%5E%7B0%7Df%28C2H4%29%2B1%5CDelta%20H%5E%7B0%7Df%28H2O%29%5D)
ΔH = -277.69-(52.26-285.83) = -44.12 KJ
