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ludmilkaskok [199]
3 years ago
9

I need help with this ASAP!!!

Chemistry
2 answers:
RideAnS [48]3 years ago
7 0
You need help with what?
lisabon 2012 [21]3 years ago
3 0
A is 1
B is 1
C is 1/1836
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0.000000655 mL in scientific notation
alina1380 [7]

Answer:

<u>The answer is 6.55 * 10⁻⁷</u>

Explanation:

Let's write 0.000000655 mL in scientific notation:

The first step is you have to move the decimal place until you have a number between 1 and 10. If you keep moving the decimal point to the right in 0.000000655 you will get 6.55.

Now, the second step is you count how many places you moved the decimal point. You moved it 7 places to the right to change 0.000000655 to 6.55.

Finally, You need to show that you moved the decimal point 7 places to the right by noting that the number should be multiplied by 10⁻⁷ because a power of ten with a negative exponent, such as 10⁻⁷, means the decimal was moved to the right.

<u>The answer is 6.55 * 10⁻⁷</u>

3 0
3 years ago
Un mol de Neón ocupa un volumen de 5 lt y una temperatura 300°K, cuál será su volumen si la temperatura disminuye en 50 °K, P y
Anna [14]

Answer:

No hoblo englas

Explanation:

7 0
2 years ago
Why are scientific method important in the study of science
Sergio [31]

Answer: The scientific method. When conducting research, scientists use the scientific method to collect measurable, empirical evidence in an experiment related to a hypothesis (often in the form of an if/then statement), the results aiming to support or contradict a theory.

Explanation:

6 0
3 years ago
What is the final concentration if water is added to 0.25 L of a 8M NaOH solution to make 4.0 L of a diluted NaOH solution?
mojhsa [17]

Answer:

the answer is 0.5 naoh solution

6 0
3 years ago
21 mL It required 42.35 mL of H2SO4 to neutralize 21.17 mL of 0.5000 M NaOH. Calculate the concentration of H2SO4
bija089 [108]
The balanced equation for the above reaction is 
2NaOH + H₂SO₄ ---> Na₂SO₄ + 2H₂O
stoichiometry of NaOH to H₂SO₄ is 2:1
number of NaOH moles required-0.5000 M / 1000 mL/L x 21.17 mL = 0.010585 mol
According to stoichiometry, acid moles required are 1/2 of the base moles reacted
Therefore number of H₂SO₄ moles reacted - 0.010585 /2  mol
Number of moles in 42.35 mL of H₂SO₄ - 0.010585 /2 mol
Therefore in 1 L solution - (0.010585) /2 / 42.35 mL x 1000 mL/L = 0.125 M
Molarity of H₂SO₄ - 0.125 M
5 0
3 years ago
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