Answer:
A) 1.12m
B) 7.92 x 10^(-3) m
Explanation:
A) Formula for reynolds number to reflect this question is given as;
R_e = Vx/v
Where;
V is velocity
x is polar coordinate where the boundary layer will become turbulent.
R_e is reynolds number.
Reynolds number for turbulent flow of flat plates has a value of 5 x 10^(5)
v is kinematic velocity
From water tables at standard conditions, kinematic viscosity is 1.12 x 10^(-6) m²/s
Now, R_e = Vx/v
We are looking for x, so let's make x the subject.
x = v•R_e/V
Thus, plugging in the relevant values to obtain;
x = [1.12 x 10^(-6) x 5 x 10^(5)]/0.5
x = 1.12m
B) The boundary layer thickness at the point where the flow becomes turbulent is given by;
δ = 5√(vx/V)
Where;
V is velocity
x is polar coordinate where the boundary layer will become turbulent.
R_e is reynolds number.
Reynolds number for turbulent flow of flat plates has a value of 5 x 10^(5)
v is kinematic velocity
Plugging in the relevant values to get ;
δ = 5√(1.12 x 10^(-6)•1.12/0.5)
δ = 5√(2.5088 x 10^(-6)
δ = 7.92 x 10^(-3) m
