All categories

3 years ago

Identify five safety hazards that should be included in the design of the school

Engineering

1 answer:

erik [133]3 years ago

7 0

Answer:

1) function of fire doors and making sure theyre properly wired to fire alarms

2) proper water piping and purifaction for water fountains and sinks.

3) falty sprinkler systems/rsuty sprikler systems that wont work

4) weather durable roofing and walls for storms and snow depending on were your located .

5) rsuted pipes in showers or fountains that could give you tetnus or other disaeases

Explanation:

HOPE THIS HELPS good luck!!

You might be interested in

The coefficient of friction is found by ?

nignag [31]

Answer:

The formula to calculate the coefficient of friction is μ = f÷N. The friction force, f, always acts in the opposite direction of the intended or actual motion, but only parallel to the surface.

7 0

3 years ago

Students are expected to respond to one of the two questions described below. Students should provide examples to clarify their

Flura [38]

Answer:

can u explain what we are answering?

Explanation:

7 0

4 years ago

Sheet metal cutting operation along a straight line between two cutting edges is called Shearing Operation's. a)- True b)-False

AURORKA [14]

Answer: True

Explanation: The process in sheet metal which separates the metal sheet in straight line by cutting is known as shearing operation.The process of shearing is carried out by application of shearing forces on the metal sheet. this operation separates the metal sheet into two parts by the edges. They have the certain limited tolerance. Therefore the given statement in the question is true.

8 0

4 years ago

An air conditioner operating at steady state maintains a dwelling at 70°F on a day when the outside temperature is 99°F. The rat

IrinaVladis [17]

Answer:

a) the coefficient of performance of the air conditioner is 3.5729

- the power input required for a reversible air conditioner is 0.645 hp

- the coefficient of performance for the reversible air conditioner is 18.2759

Explanation:

Given the data in the question;

Lower Temperature $T_L$ = 70°F = ( 70 + 460 )R = 530 R

Higher Temperature $T_H$ = 99° F = ( 99 + 460 )R = 559 R

Cooling Load $Q_L$ = 30000 Btu/h

we know that 1 hp = 2544.43 Btu/h

Net power input P = 3.3 hp = ( 3.3 × 2544.43 )Btu/h = 8396.619 Btu/h

Coefficient of performance of the air conditioner;

$COP_{air-condition$ = Cooling Load $Q_L$ / power P

we substitute

$COP_{air-condition$ = 30000 Btu/h / 8396.619 Btu/h

$COP_{air-condition$ = 3.5729

Therefore, the coefficient of performance of the air conditioner is 3.5729

- Power input required ( in hp )

$Q_L$ / $P_{required$ = $T_L$ / ( $T_H$ - $T_L$ )

we substitute

30000 Btu/h / $P_{required$ = 530 R / ( 559 R - 530 R )

30000 Btu/h / $P_{required$ = 530 R / 29 R

we solve for $P_{required$

$P_{required$ = ( 30000 Btu/h × 29 R ) / 530 R

$P_{required$ = ( 870000 Btu/h / 530 )

$P_{required$ = 1641.5094 Btu/h

we know that; 1 hp = 2544.43 Btu/h

so;

$P_{required$ = ( 1641.5094 / 2544.43 ) hp

$P_{required$ = 0.645 hp

Hence, the power input required for a reversible air conditioner is 0.645 hp

- the coefficient of performance for the reversible air conditioner;

$COP_{rev-air-condition$ = $T_L$ / ( $T_H$ - $T_L$ )

we substitute

$COP_{rev-air-condition$ = 530 R / ( 559 R - 530 R )

$COP_{rev-air-condition$ = 530 R / 29 R

$COP_{rev-air-condition$ = 18.2759

Hence, the coefficient of performance for the reversible air conditioner is 18.2759

3 0

3 years ago

Which type of snap ring plier expands the snap ring for removal?

4vir4ik [10]

Answer:

c I think so haven't took engineering in ages

4 0

3 years ago