Answer:
The lifetime of the particle is
Explanation:
From the question we are told that
The average rest energy is
The intrinsic width is
The lifetime is mathematically represented as
Where h is the Planck's constant with a value of
substituting values
The position at time t is
x(t) = 0.5t³ - 3t² + 3t + 2
When the velocity is zero, the derivative of x with respect to t is zero. That is,
x' = 1.5t² - 6t + 3 = 0
or
t² - 4t + 2 = 0
Solve with the quadratic formula.
t = (1/2) [ 4 +/- √(16 - 8)] = 3.4142 or 0.5858 s
When t =0.5858 s, the position is
x = 0.5(0.5858³) - 3(0.5858²) + 3(0.5858) + 2 = 2.828 m
When t=3.4142 s, the position is
x = 0.5(3.4142³) - 3(3.4142²) + 3(3.4142) + 2 = -2.828 m
Reject the negative answer.
Answer:
The velocity is zero when t = 0.586 s, and the distance is 2.83 m
When the acceleration is zero, the second derivative of x with respect to t is zero. That is,
3t - 6 = 0
t = 2
The distance traveled is
x = 0.5(2³) - 3(2²) + 3(2) + 2 = 0
Answer:
When the acceleration is zero, t = 2 s, and the distance traveled is zero.
Answer:
d. W<0 and Q<0
Explanation:
Heat (Q) and work (W) are ways of exchange of energy.
When a system gains heat, that its temperature increases, and, because the heat flows to the system it's positive (Q>0), and when it loses heat the inverse happens and Q<0.
When the system expands, it does work at the surroundings, so the work is going from the system, and it's positive (W >0), when the inverse happens, the work goes to the system and W<0.
So, the gas is compressed, then W<0, and it warms up. To cold it, the tank has put a tub with water, do the gas will lose heat and Q<0.
13.1 km/s, that is the mean orbital velocity of Jupiter around the sun