Answer:
2.49 seconds
Explanation:
From the question,
a = (v-u)/t............................ Equation 1
Where a = acceleration, v = final velocity, u = initial velocity, t = time
Make t the subject of the equation
t = (v-u)/a.......................... Equation 2
Given: v = 6.5 m/s, u = 11 m/s, a = -1.81 m/s²
Substitute these values into equation 2
t = (6.5-11)/(-1.81)
t = -4.5/-1.81
t = 2.49 s
Answer:
E = 3.049 N/C
Explanation:
Induced electric field = e/2 *(pi) *r
Induced electric field = e /(3.14 *19.5) - Eq (1)
e = (pi)r^2*B/t
= 3.14 * (19.5/2*100)^2 * 0.50 T/ 0.1
= 1.867 V
Substituting this value in equation 1, we get –
E = 1.867 V/(3.14 *19.5/100)
E = 3.049 N/C
The magnitude of the electric current is directly proportional to the "Electric Charge" <span>of the electric field.
Hope this helps!</span>
1 volt = 1 joule per coulomb
50 volts = 50 joules per coulomb
50 joules/coulomb times 6 coulombs = 300 joules