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Lady bird [3.3K]
3 years ago
11

A 958-N rocket is coming in for a vertical landing. It starts with a downward speed of 25 m/s and must reduce its speed to 0m/s

in 8.0 seconds for the final landing. During this landing maneuver, what must be the thrust due to the rockets engines?
Physics
1 answer:
Art [367]3 years ago
3 0

Answer:

T=1263.16N

Explanation:

A 958-N rocket is coming in for a vertical landing. It starts with a downward speed of 25 m/s and must reduce its speed to 0m/s in 8.0 seconds for the final landing. During this landing maneuver, what must be the thrust due to the rockets engines?

force is that which tends to cane a body state of rest or uniform motion in a straight line

it is also the pull or pus on an object.

the forces involved here to get the thrust on an object, are the weight and the force of gravity

W=mg

958=m*9.81

m=958/9.81

m=97.655kg

T=m(g+a)................................1

to get a

v=u+at

a=dv/dt

a=25/8

a=3.125m/s^2

acceleration is change in velocity per time

juxtaposing into the equation 1

T=97.655(9.81+3.125)

T=1263.16N

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A river flows due east at 1.70 m/s. A boat crosses the river from the south shore to the north shore by maintaining a constant v
ad-work [718]

Answer:

a)

v = 14.1028 m/s  

∅ = 83.0765° north of east

b)

the required distance is 40.98 m

Explanation:

Given that;

velocity of the river u = 1.70 m/s

velocity of boat v = 14.0 m/s

Now to get the velocity of the boat relative to shore;

( north of east), we say

a² + b² = c²

(1.70)² + (14.0)² = c²

2.89 + 196 = c²

198.89 = c²

c = √198.89

c = 14.1028 m/s  

tan∅ = v/u = 14 / 1.7 =  8.23529

∅ = tan⁻¹ ( 8.23529 ) = 83.0765° north of east

Therefore, the velocity of the boat relative to shore is;

v = 14.1028 m/s  

∅ = 83.0765° north of east

b)  

width of river = 340 m,

ow far downstream has the boat moved by the time it reaches the north shore in meters = ?

we say;

340sin( 90° - 83.0765°)

⇒ 340sin( 6.9235°)

= 40.98 m

Therefore, the required distance is 40.98 m

5 0
3 years ago
A circuit is built based on the circuit diagram shown. What is the current in the 50 Ω resistor
In-s [12.5K]

Answer:

1.2 A

Explanation:

From the diagram attached, The three resistors are parallel because the each ends of the resistors are connected together. Since they are in parallel, the voltage across each resistor is the same. The voltage source connected in parallel to the resistors is 60 V. Therefore the voltage across the 50 Ω resistor is 60 V. Using ohm law:

Voltage (V) = Current (I) × Resistance (R)

V = IR

I = V/R

I = 60 V/ 50 Ω

I = 1.2 A

The current in the 50 Ω resistor is 1.2 A

5 0
3 years ago
Sandy is whirling a ball attached to a string in a horizontal circle over his head. If Sandy doubles the speed of the ball, what
jeka57 [31]

The tension in the string B) It quadruples.

Explanation:

The ball is in uniform circular motion in a horizontal circle, so the tension in the string is providing the centripetal force that keeps the ball in circular motion. So we can write:

T= m\frac{v^2}{r}

where:

T is the tension in the string

m is the mass of the ball

v is the speed of the ball

r is the radius of the circle (the lenght of the string)

In this problem, we are told that the speed of the ball is doubled, so

v' = 2v

Substituting into the previous equation, we find the new tension in the string:

T' = m \frac{(2v)^2}{r}=4(m\frac{v^2}{r})=4T

Therefore, the tension in the string will quadruple.

Learn more about circular motion:

brainly.com/question/2562955

brainly.com/question/6372960

#LearnwithBrainly

6 0
3 years ago
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Brainliest if correct Question 10 of 10
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Answer:

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Explanation:

Conduction is the movement of thermal energy without the actual movement of the particles of a body. They particles only collide with each other and transfer energy in the process while maintaining their mean positions.

5 0
2 years ago
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