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vazorg [7]
4 years ago
9

You drive from your house to the dry cleaners, which is 12 miles east of your house. You then drive to the grocery store from th

e dry cleaners. The grocery store is 15 miles west of your house. What distance did you cover?

Physics
1 answer:
kumpel [21]4 years ago
3 0

Answer:

39 miles

Explanation:

we will make your house to be the central point in the four cardinal points.

Please follow the diagram on the attachment to get the movement clearly.

First, you move to a dry cleaners 12miles east of your house, and then to a grocery store 15miles west of your house.

This means you must have moved back to your house before going to the grocery which is 15miles west of your house.

so to and fro from your house to dry cleaners = 12*2 = 24 miles.

Then the total distance you cover will be = 24 +15 = 39 miles

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erik [133]

Answer:

Initial pressure = 6 atm. Work = 0.144 J

Explanation:

You need to know the equation P1*V1=P2*V2, where P1 is the initial pressure, V1 is the initial volume, and P2 and V2 are the final pressure and volume respectively. So you can rearrange the terms and find that (1.2*0.05)/(0.01) = initial pressure = 6 atm. The work done by the system can be obtained calculating the are under the curve, so it is 0.144J

4 0
3 years ago
50.0 meters away from a building. Tip of the building makes an angle of 63.0° with the horizontal. What is the height of the bui
soldi70 [24.7K]

Answer:

98.13m

Explanation:

Complete question

Daniel is 50.0 meters away from a building. Tip of the building makes an angle of 63.0° with the horizontal. What is the height of the building

CHECK THE ATTACHMENT

From the figure, using trigonometry

Tan(θ ) = opposite/adjacent

Where Angle (θ )= 63°

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Adjacent= 50 m

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Tan(63)= X/50

1.9626= X/50

X= 1.9626 × 50

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8 0
3 years ago
What is Vatiable Velocity?​
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3 years ago
Place the left charge at the 2 cm position and the right one at the 4 cm position. Vary the left and right charge to the values
Vlad1618 [11]

Answer:

Explanation:

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F = k q₁ q₂ / d²

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= 9 x 10⁹ x 1 x 4 x 10⁻¹² / ( 2 x 10⁻² )²

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= 9 x 10⁹ x 4 x 1 x 10⁻¹² / ( 2 x 10⁻² )²

= 9 x 10 = 90 N

force between 2μC and  2μC

= 9 x 10⁹ x 2 x 2 x 10⁻¹² / ( 2 x 10⁻² )²

= 9 x 10 = 90 N

force between 1μC and  2μC

= 9 x 10⁹ x 1 x 2 x 10⁻¹² / ( 2 x 10⁻² )²

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force between 1μC and  8μC

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force between 2μC and  8μC

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Left Charge   Right Charge Resulting force(N)

1μC                     4μC                  90 N

4μC                   1μC                    90 N

2μC                  2μC                    90 N

1μC                    2μC                   45 N

1μC                  8μC                    180 N

2μC                  8μC                  360 N

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