<u>Hello and Good Morning/Afternoon</u>:
<em>Original Question: C₂H₅OH + __O₂ → __CO₂ + __ H₂O</em>
<u>To balance this equation</u>:
⇒ must ensure that there is an equal number of elements on both sides of the equation at all times
<u>Let's start balancing:</u>
- On the left side of the equation, there are 2 carbon molecule
⇒ but only so far one on the right side
C<em>₂H₅OH + __O₂ → 2CO₂ + __ H₂O</em>
- On the left side of the equation, there are 6 hydrogen molecules
⇒ but only so far two on the right side
C<em>₂H₅OH + __O₂ → 2CO₂ + 3H₂O</em>
- On the right side of the equation, there are 7 oxygen molecules
⇒ but only so far three on the left side
C<em>₂H₅OH + 3O₂ → 2CO₂ + 3H₂O</em>
<u>Let's check and make sure we got the answer:</u>
C<em>₂H₅OH + 3O₂ → 2CO₂ + 3H₂O</em>
<em> 2 Carbon ⇔ 2 Carbon</em>
<em> 6 Hydrogen ⇔ 6 Hydrogen</em>
<em> 7 Oxygen ⇔ 7 oxygen</em>
<u>Thefore the coefficients in order are</u>:
⇒ 1, 3, 2, 3
<u>Answer: 1,3,2,3</u>
Hope that helps!
#LearnwithBrainly<em> </em>
Answer:
The rock's speed after 5 seconds is 98 m/s.
Explanation:
A rock is dropped off a cliff.
It had an initial velocity of 0 m/s. And now it is moving downwards under the influence of gravitational force with the gravitational acceleration of 9.8 m/s².
Speed after 5 seconds = V
We know that acceleration = average speed/time
In our case,
g = ((0+V)/2)/5
9.8*5 = V/2
=> V = 2*9.8*5
V = 98 m/s
Answer:
E. The wheel with spokes has about twice the KE.
See explanation in: https://quizlet.com/100717504/physics-8-mc-flash-cards/
Answer:
(a) r = 1.062·R
= ![\frac{531}{500} R_E](https://tex.z-dn.net/?f=%5Cfrac%7B531%7D%7B500%7D%20R_E)
(b) r = ![\frac{33}{25} R_E](https://tex.z-dn.net/?f=%5Cfrac%7B33%7D%7B25%7D%20R_E)
(c) Zero
Explanation:
Here we have escape velocity v
given by
and the maximum height given by
![\frac{1}{2} v^2-\frac{GM}{R_E} = -\frac{GM}{r}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20v%5E2-%5Cfrac%7BGM%7D%7BR_E%7D%20%3D%20-%5Cfrac%7BGM%7D%7Br%7D)
Therefore, when the initial speed is 0.241v
we have
v =
so that;
v² =
v² = ![{\frac{0.116162\times GM}{R_E} }](https://tex.z-dn.net/?f=%7B%5Cfrac%7B0.116162%5Ctimes%20GM%7D%7BR_E%7D%20%7D)
is then
![\frac{1}{2} {\frac{0.116162\times GM}{R_E} }-\frac{GM}{R_E} = -\frac{GM}{r}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20%7B%5Cfrac%7B0.116162%5Ctimes%20GM%7D%7BR_E%7D%20%7D-%5Cfrac%7BGM%7D%7BR_E%7D%20%3D%20-%5Cfrac%7BGM%7D%7Br%7D)
Which gives
or
r = 1.062·R
(b) Here we have
![K_i = 0.241\times \frac{1}{2} \times m \times v_e^2 = 0.241\times \frac{1}{2} \times m \times \frac{2GM}{R_E} = \frac{0.241mGM}{R_E}](https://tex.z-dn.net/?f=K_i%20%3D%200.241%5Ctimes%20%5Cfrac%7B1%7D%7B2%7D%20%5Ctimes%20m%20%5Ctimes%20v_e%5E2%20%3D%200.241%5Ctimes%20%5Cfrac%7B1%7D%7B2%7D%20%5Ctimes%20m%20%20%5Ctimes%20%5Cfrac%7B2GM%7D%7BR_E%7D%20%3D%20%5Cfrac%7B0.241mGM%7D%7BR_E%7D)
Therefore we put
in the maximum height equation to get
![\frac{0.241}{R_E} -\frac{1}{R_E} =-\frac{1}{r}](https://tex.z-dn.net/?f=%5Cfrac%7B0.241%7D%7BR_E%7D%20-%5Cfrac%7B1%7D%7BR_E%7D%20%3D-%5Cfrac%7B1%7D%7Br%7D)
From which we get
r = 1.32·R
(c) The we have the least initial mechanical energy, ME given by
ME = KE - PE
Where the KE = PE required to leave the earth we have
ME = KE - KE = 0
The least initial mechanical energy to leave the earth is zero.