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2 years ago

What is the internal energy of 4.50 mol of N2 gas at 253°C? To solve this

Physics

1 answer:

Finger [1]2 years ago

6 0

The internal energy of the gas is 49,200 J

Explanation:

The internal energy of a diatomic gas, such as $N_2$ , is given by

$U=\frac{5}{2}nRT$

where

n is the number of moles

R is the gas constant

T is the absolute temperature of the gas

For the gas in this problem, we have:

n = 4.50 (number of moles)

R = 8.31 J/(mol·K) (gas constant)

$T=253^{\circ} + 273 = 526 K$ (absolute temperature)

Substituting, we find:

$U=\frac{5}{2}(4.50)(8.31)(526)=49,200 J$

Learn more about ideal gases:

brainly.com/question/9321544

brainly.com/question/7316997

brainly.com/question/3658563

#LearnwithBrainly

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When light is incident normally on the interface between two transparent optical media, the intensity of the reflected light is

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2 years ago

inysia [295]

Hello and Good Morning/Afternoon:

Original Question: C₂H₅OH + __O₂ → __CO₂ + __ H₂O

To balance this equation:

⇒ must ensure that there is an equal number of elements on both sides of the equation at all times

Let's start balancing:

On the left side of the equation, there are 2 carbon molecule

⇒ but only so far one on the right side

C₂H₅OH + __O₂ → 2CO₂ + __ H₂O

On the left side of the equation, there are 6 hydrogen molecules

⇒ but only so far two on the right side

C₂H₅OH + __O₂ → 2CO₂ + 3H₂O

On the right side of the equation, there are 7 oxygen molecules

⇒ but only so far three on the left side

C₂H₅OH + 3O₂ → 2CO₂ + 3H₂O

Let's check and make sure we got the answer:

C₂H₅OH + 3O₂ → 2CO₂ + 3H₂O

2 Carbon ⇔ 2 Carbon

6 Hydrogen ⇔ 6 Hydrogen

7 Oxygen ⇔ 7 oxygen

Thefore the coefficients in order are:

⇒ 1, 3, 2, 3

Answer: 1,3,2,3

Hope that helps!

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1 year ago

Suppose a rock is dropped off a cliff with an initial speed of 0m/s. What is the rocks speed after 5 secounds, in m/s, if it enc

Tasya [4]

Answer:

The rock's speed after 5 seconds is 98 m/s.

Explanation:

A rock is dropped off a cliff.

It had an initial velocity of 0 m/s. And now it is moving downwards under the influence of gravitational force with the gravitational acceleration of 9.8 m/s².

Speed after 5 seconds = V

We know that acceleration = average speed/time

In our case,

g = ((0+V)/2)/5

9.8*5 = V/2

=> V = 2*9.8*5

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2 years ago

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Two wheels having the same radius and mass rotate at the same angular velocity ((Figure 1) ). One wheel is made with spokes so n

liubo4ka [24]

Answer:

E. The wheel with spokes has about twice the KE.

See explanation in: https://quizlet.com/100717504/physics-8-mc-flash-cards/

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2 years ago

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A projectile is shot directly away from Earth's surface. Neglect the rotation of the Earth. What multiple of Earth's radius RE g

7nadin3 [17]

Answer:

(a) r = 1.062·R $_E$ = $\frac{531}{500} R_E$

(b) r = $\frac{33}{25} R_E$

Explanation:

Here we have escape velocity v $_e$ given by

$v_e =\sqrt{\frac{2GM}{R_E} }$ and the maximum height given by

$\frac{1}{2} v^2-\frac{GM}{R_E} = -\frac{GM}{r}$

Therefore, when the initial speed is 0.241v $_e$ we have

v = $0.241\times \sqrt{\frac{2GM}{R_E} }$ so that;

v² = $0.058081\times {\frac{2GM}{R_E} }$

v² = ${\frac{0.116162\times GM}{R_E} }$

$\frac{1}{2} v^2-\frac{GM}{R_E} = -\frac{GM}{r}$ is then

$\frac{1}{2} {\frac{0.116162\times GM}{R_E} }-\frac{GM}{R_E} = -\frac{GM}{r}$

Which gives

$-\frac{0.941919}{R_E} = -\frac{1}{r}$ or

r = 1.062·R $_E$

(b) Here we have

$K_i = 0.241\times \frac{1}{2} \times m \times v_e^2 = 0.241\times \frac{1}{2} \times m \times \frac{2GM}{R_E} = \frac{0.241mGM}{R_E}$

Therefore we put $\frac{0.241GM}{R_E}$ in the maximum height equation to get

$\frac{0.241}{R_E} -\frac{1}{R_E} =-\frac{1}{r}$

From which we get

r = 1.32·R $_E$

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The least initial mechanical energy to leave the earth is zero.

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2 years ago

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