Answer:
a)α = - 0.415 rad/s²
b)t=226.68 sec
Explanation:
Given
Initial angular speed
ωi= 900 rev/min
ωi= 94.24
θ = 1700 rev
We know that
1 rev = 2π rad
θ = 3400π rad
Final angular speed ωf=0 rad/s
α=Angular acceleration
We know that
ωf² = ωi²+ 2 α θ
0² = 94.24²+ 2 x 3400π x α
α = - 0.415 rad/s²
Negative sign indicates that acceleration and speed is in opposite direction.
We also know that
ωf = ωi+ α t
0 = 94.24 - 0.415 x t
t=226.68 sec
a)α = - 0.415 rad/s²
b)t=226.68 sec
Answer:Impossible to answer without knowing their actual initial speeds
Explanation:
Given
Ball A launched at angle of
Ball B is launched at angle of
At the highest point Ball vertical velocity will be and there will be only horizontal velocity i.e. and
where is the velocity of A & B
thus to find which one is greater we need to know their initial velocity.
It is impossible to know which one have higher velocity at highest point.
Answer:
The work function of the metal is 2.226 eV.
Explanation:
Given;
wavelength of the violet light, λ = 427 nm = 427 x 10⁻⁹ m
maximum kinetic energy, K.E = 0.684 eV
The energy of the incident light is calculated as;
Apply Einstein's photoelectric equation;
E = Ф + K.E
where;
Ф is the work function of the metal
Ф = E - K.E
Ф = 2.91 eV - 0.684 eV
Ф = 2.226 eV.
Therefore, the work function of the metal is 2.226 eV.