A cooling fan is turned off when it is running at 900 rev/min. It turns 1700 revolutions before it comes to a stop.
1 answer:
Answer:
a)α = - 0.415 rad/s²
b)t=226.68 sec
Explanation:
Given
Initial angular speed
ωi= 900 rev/min
ωi= 94.24
θ = 1700 rev
We know that
1 rev = 2π rad
θ = 3400π rad
Final angular speed ωf=0 rad/s
α=Angular acceleration
We know that
ωf² = ωi²+ 2 α θ
0² = 94.24²+ 2 x 3400π x α
α = - 0.415 rad/s²
Negative sign indicates that acceleration and speed is in opposite direction.
We also know that
ωf = ωi+ α t
0 = 94.24 - 0.415 x t
t=226.68 sec
a)α = - 0.415 rad/s²
b)t=226.68 sec
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Answer:
(a) 25 m
(b) 75 m
Explanation:
Given that the jogger runs at a constant rate of 10.0 m every 2.0 seconds.
So, the speed of the jogger,
Let d be the distance covered by him in time, t s.
As distance=(speed) x (time)
So,
From equation (i)
As the jogger starts from origin, so, the distance, , also represents the position of the jogger at the time
s.
The position-time graph has been shown.
(a) From equation (ii), for t=5.0 s
So, the jogger is at a distance of 25 m from the origin.
(b) Similarly, for t=15.0 s
So, the jogger is at a distance of 75 m from the origin.
Answer:
x = 2.044 m
Explanation:
given data
initial vertical component of velocity = Vy = 2sin18
initial horizontal component of velocity = Vx = 2cos18
distance from the ground yo = 5m
ground distance y = 0
from equation of motion
solving for t
t = 1.075 sec
for horizontal motion
x = 2cos18*1.075
x = 2.044 m
