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Andreas93 [3]
2 years ago
13

6. What are the methods to control noise pollution?​

Physics
2 answers:
max2010maxim [7]2 years ago
8 0

Answer:

You have to:

a) Improve your insulation.

b) Install a fence

c) Use modern Acoustic wall panels

d) Plant trees

e) Reduce electronic volumes,e.t.c.

Explanation:

okay.

Phoenix [80]2 years ago
7 0

Answer: Some of the ways to control noise pollution are as follows: (1) Control at Receiver's End (2) Suppression of Noise at Source (3) Acoustic Zoning (4) Sound Insulation at Construction Stages (5) Planting of Trees (6) Legislative Measures.

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A 59 kg physics student is riding her 220 kg Harley at 12 m/s when she has a head-on collision with a 2.1 kg pigeon flying the o
IgorLugansk [536]

Answer:

Explanation:

Using conservation of momentum

m_1=59+220=279kg

m_2=2.1kg

U_1=12m/s

U_2=-44m/s

m_1U_1+m_2U_2=(m_1+m_2)V\\\\\frac{278\times 12-2.1\times 44}{279+2.1}=V\\\\V=11.58m/s

6 0
3 years ago
Plants release water vapor into the atmosphere through the process called _____.
timofeeve [1]
The process is called transpiration  <span />
6 0
3 years ago
Read 2 more answers
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Elina [12.6K]

Answer:

E = h ν        energy of electromagnetic particle  

(b)   has the greater frequency

5 0
1 year ago
What is the answer?
Andrews [41]

Answer:

6.26 m/s

Explanation:

Pretty slow.... the PE (Potential Energy) at 2m will be converted to KE (Kinetic Energy) at the bottom of the track (neglecting friction)

PE    =   KE

mgh = 1/2 mv^2     divide both sides of the equation by 'm'

gh    = 1/2 v^2             multiply both sides by 2

2 gh = v^2               take sqrt of both sides

v = sqrt ( 2gh) = sqrt ( 2*9.81*2) = 6.26 m/s

3 0
1 year ago
How long (in seconds) does it take a car accelerating at 3.1 m/s2 to go from rest<br> to 51 m/s?
Nesterboy [21]

Answer:

 t  = 16.5s

Explanation:

Given parameters:

Acceleration = 3.1m/s²

Initial velocity  = 0m/s

Final velocity  = 51m/s

Unknown:

Time taken  = ?

Solution:

To solve this problem we need to reiterate that acceleration is the rate of change of velocity with time.

So;

        Acceleration  = \frac{v  - u }{t}  

v is the final velocity

u is the initial velocity

t is the time taken

  So;

       3.1  = \frac{51 - 0}{t}  

    3.1t  = 51

       t  = 16.5s

8 0
3 years ago
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