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Radda [10]
4 years ago
13

Which nerve cells in your eyes react to color

Physics
2 answers:
OlgaM077 [116]4 years ago
5 0
The nublea.

hopefully i helped. if not im so very sorry!!!
DochEvi [55]4 years ago
4 0
I think nebula?Sorry if I'm wrong
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A car with a mass of 1600 kg is towing a trailer with a mass of 420 kg. The car
Gekata [30.6K]

Answer:

1.63366

Explanation:

I got this answer from calculator soups physics calculators. I really recommend their website for formulas.  

3 0
3 years ago
Which rule is used to determine the direction of the magnetic field and force produced by a moving electrical charge?
densk [106]

Answer:

The right hand rule

Explanation:

The thumb indicating the direction of the moving charge, and the fingers indicating the direction of the magnetic field vectors in the right hand rule.

7 0
3 years ago
Distance Between Two Cars A car leaves an intersection traveling west. Its position 4 sec later is 19 ft from the intersection.
faltersainse [42]

Answer:

The answer to the question is;

The rate at which the distance between the two cars is changing is equal to 14.4 ft/sec.

Explanation:

We note that the distance  traveled by each car after 4 seconds is

Car A = 19 ft in the west direction.

Car B = 26 ft in the north direction

The distance between the two cars is given by the length of the hypotenuse side of a right angled triangle with the north being the y coordinate and the  west being the x coordinate.

Therefore, let the distance between the two cars be s

we have

s² = x² + y²

= (19 ft)² + (26 ft)² = 1037 ft²

s = \sqrt{1037 ft^2} = 32.202 ft.

The rate of change of the distance from their location 4 seconds after they commenced their journeys is given by;

Since s² = x² + y² we have

\frac{ds^{2} }{dt} = \frac{dx^{2} }{dt}  + \frac{dy^{2} }{dt}

→ 2s\frac{ds }{dt} = 2x\frac{dx}{dt}  + 2y\frac{dy }{dt} which gives

s\frac{ds }{dt} = x\frac{dx}{dt}  + y\frac{dy }{dt}

We note that the speeds of the cars were given as

Car B moving north = 12 ft/sec, which is the y direction and

Car A moving west = 8 ft/sec which is the x direction.

Therefore

\frac{dy }{dt} =  12 ft/sec and

\frac{dx}{dt} = 8 ft/sec

s\frac{ds }{dt} = x\frac{dx}{dt}  + y\frac{dy }{dt} becomes

32.202 ft.\frac{ds }{dt} = 19 ft \times 8 \frac{ft}{sec}  + 26ft\times 12\frac{ft}{sec}  = 464 ft²/sec

\frac{ds }{dt} = \frac{464\frac{ft^{2} }{sec} }{32.202 ft.} = 14.409 ft/sec ≈ 14.4 ft/sec to one place of decimal.

3 0
3 years ago
How much work, in Joules, is required to stop a 1,168 kg car moving with a speed of 24 km/hr?
ANEK [815]
24km/hour=(20/3)m/s
Hence, W=1/2*1168kg*[(20/3)/m/s]^2=25955.56J

6 0
2 years ago
a roller coaster is traveling at 13m/s when it approaches a hill that is 400m long. heading down the hill, it accelerates 4.0m/s
Degger [83]
We will apply the equation:
2as = v² - u²
v = √(2as + u²)
v = √(2 x 4 x 400 + 13²)
v = 58 m/s

hope this helps
7 0
3 years ago
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