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ipn [44]
3 years ago
7

a sound wave travels at 330 m/sec and has a wavelenght of 2meters. calcuate the frequency and period

Physics
1 answer:
Sergio039 [100]3 years ago
7 0

The frequency of any wave is  (speed) / (wavelength).

 Frequency = (330 m/s) / (2m)  =  165 per second = <em>165 Hz</em>.

Period = 1 / frequency  =  1 / (165 per second) = <em>0.0061 second </em>


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A charged particle is moving in a uniform magnetic field at a speed of 8.2Ã10^3 m/s in a direction 87° from the direction of th
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Answer:

Magnetic field, B = 0.042 T

Explanation:

It is given that,

Speed of charged particle, v=8.2\times 10^3\ m/s

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Charge, q=5.7\ \mu C=5.7\times 10^{-6}\ C

Magnetic force, F = 0.002 N

The magnetic force is given by :

F=qvB\ sin\theta

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B=\dfrac{F}{qv\ sin\theta}

B=\dfrac{0.002}{5.7\times 10^{-6}\times 8.2\times 10^3\times sin(87)}

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So, the strength of the magnetic field is 0.042 Tesla. Hence, this is the required solution.

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Answer:

(i) W = 8.918 N

(ii) V = 9.1 \times 10^{-4} m^3

(iii) d = 9.1 cm

Explanation:

Part a)

As we know that weight of cube is given as

W = mg

W = \rho V g

here we know that

\rho = 0.91 g/cm^3

Volume = L^3

Volume = 10^3 = 1000 cm^3

now the mass of the ice cube is given as

m = 0.91 \times 1000 = 910 g

now weight is given as

W = 0.910 \times 9.8 = 8.918 N

Part b)

Weight of the liquid displaced must be equal to weight of the ice cube

Because as we know that force of buoyancy = weight of the of the liquid displaced

W_{displaced} = 8.918 N

So here volume displaced is given as

\rho_{water}Vg = 8.918

1000(V)9.8 = 8.918

V = 9.1 \times 10^{-4} m^3

Part c)

Let the cube is submerged by distance "d" inside water

So here displaced water weight is given as

W = \rho_{water} (L^2 d) g

8.918 = 1000(0.10^2 \times d) 9.8

d = 0.091 m

so it is submerged by d = 9.1 cm inside water

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