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3 years ago

a sound wave travels at 330 m/sec and has a wavelenght of 2meters. calcuate the frequency and period

1 answer:

7 0

The frequency of any wave is (speed) / (wavelength).

Frequency = (330 m/s) / (2m) = 165 per second = 165 Hz.

Period = 1 / frequency = 1 / (165 per second) = 0.0061 second 

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What is second law of netwons

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Explanation:

Newton's second law says that when a constant force acts on a massive body, it causes it to accelerate.

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An engineer has the task of producing an aluminum alloy with a density of 3.0 grams per cubic centimeter. She comes up with the

pochemuha

Answer:

The best option is for the following option m = 15 [g] and V = 5 [cm³]

Explanation:

We have that the density of a body is defined as the ratio of mass to volume.

$Ro =m/V$

where:

Ro = density = 3 [g/cm³]

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For m = 7 [g] and V = 2.3 [cm³]

$Ro=7/2.3\\Ro=3.04 [g/cm^{3} ]$

For m = 10 [g] and V = 7 [cm³]

$Ro=10/7\\Ro=1.42[g/cm^{3} ]\\$

For m = 15 [g] and V = 5 [cm³]

$Ro=15/5\\Ro=3[g/cm^{3} ]\\$

For m = 21 [g] and V = 8 [cm³]

$Ro=21/8\\Ro=2.625[g/cm^{3} ]\\$

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2 years ago

A ball of moist clay falls 15.0 m to the ground. It is in contact with the ground for 20.0 ms before stopping. (a) What is the m

rosijanka [135]

Answer:

a= -0.86 m/s²

The negative sign shows that ball down the ground or moving down

Explanation:

Vf² - Vo² = 2gS

where

Vf = velocity of clay as it hits the ground

Vo = initial velocity of clay = 0

g = acceleration due to gravity = 9.8 m/sec^2 (constant)

S = distance travelled by clay = 15 m

Substituting appropriate values,

Vf² - 0 = 2(9.8)(15)

Vf = 17.15 m/sec.

Formula to use is,

V - Vf = aT

where

V = velocity of clay when it stops = 0

Vf = 17.15 m/sec (as determined above)

a = acceleration

T = 20 ms

Put the values to find acceleration

a=(V-Vf)/T

a=(0-17.15)/20

a= -0.86 m/s²

The negative sign shows that ball down the ground

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3 years ago

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Answer:

(a) 0.71 mm

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Explanation:

The width of one wire is the diameter of the wire.

(a) Let the diameter of each wire is d.

So, 10 d = 14.2 mm

d = 1.42 mm

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(b) Length, L = 10 cm

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$V =\pi\times r^2\times h \\\\V =3.14\times 0.071^2\times 10\\\\V =0.158 cm^3$

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