Answer:
Density (ρ) = 5 kilogram/cubic meter
Explanation:
Steps:
ρ =
m
V
=
10 kilogram
2 cubic meter
= 5 kilogram/cubic meter
Answer:
HBr(aq) + LiOH(aq) → LiBr(aq) + H2O(l)
Explanation:
A neutralization reaction is a process in which an acid, aqeous HBr reacts completely with an appropriate amount of base, aqueous LiOH to produce salt, aqueous LiBr and water, liquid H2O only.
HBr(aq) + LiOH(aq) → LiBr(aq) + H2O(l)
Acid + base → Salt + Water.
During this reaction, the hydrogen ion, H+, from the HBr is neutralized by the hydroxide ion, OH-, from the LiOH to form the water molecule, H2O.
Thus, it is called a neutralization reaction.
Answer:
T(initial) = 241.4˚C
Explanation:
∑q = q(metal) + q(water) = 0*
Q(metal) = (m∙c∙ΔT)Fe = 360g x 0.444j/g˚C x (45.7˚C – T(initial)) = 159.84j/˚C(45.7˚C – T(initial)) = 7304.69 j – 159.84j/˚C x T(initial)
Q(water) = (m∙c∙ΔT)water = 425g x 4.184j/g˚C x (45.7˚C - 24˚C) = 38,586.94 joules
∑[Q(metal) + Q(water)] = 7304.69j -159.84j/˚C x T(initial) + 38586.94j = 0
=> 159.84 x T(initial)j/˚C = 38586.94j
=> T(initial) = 38586.94j / 159.84j/˚C = 241.4˚C
____________________________________
*Initial equation is from Heat Loss = Heat Gained (Conservation of Energy) That is, Heat lost + (- Heat gained) = 0
=> ∑(heat loss by metal) + (- heat gained by water) = 0
using heat transfer equation with temperature change
=> mcΔT(metal) + (-mcΔT(water) = mcΔT(metal) - (mcΔT(water) = 0
Answer:
Las fuentes de luz primarias son aquellas que emiten la luz que producen. Por ejemplo: la luz de Sol, un relámpago, la de una vela,...
A su vez las fuentes primarias las podemos clasificar en: fuentes naturales y fuentes artificiales
Explanation: