All categories

3 years ago

What can bond or join together to form molecules?

Chemistry

2 answers:

ioda3 years ago

5 0

Answer:

Atoms.

They come together so they can form molecules (because of their electrons)

It becomes a covalent bond

Explanation:

yan [13]3 years ago

3 0

The answer to this question would be atoms.

You might be interested in

What is the volume of 500g of CO2?

Airida [17]

Weighs 0.001836 gram per cubic centimeter or 1.836 kilogram per cubic meter

Try to see if this helps

3 0

3 years ago

Read 2 more answers

Which of the statements about elements is true?

Jet001 [13]

1. No two elements have the same kind of atom.

Explanation:

The correct of all statement is that no two elements have the same kind of atoms.

Every element have different atoms.

Over a hundred elements have been identified by scientists.
Atoms are the smallest particles that takes part in chemical reactions.
Elements are distinct substances that cannot be split.
Atoms of all elements do not have the same mass and volume. Isotopes are examples.
It is true that atoms of all elements have different masses and also different volumes.
The volume of an atom is function of the number of electrons it contains.

learn more:

Dalton model of the atom brainly.com/question/1979129

#learnwithBrainly

3 0

3 years ago

Read 2 more answers

I don't need to know why i just want the awnser

Lubov Fominskaja [6]

Answer:

I remember doing this in 7th,

1. D

2. B or D, more leaning on B though

3. A

4 0

3 years ago

At 500K, the equilibrium constant for the reaction N2O4D2NO2 is 1.5 x 10^3. What is the equilibrium constant for the reaction: 6

Veronika [31]

Answer:

K = 2.96x10⁻¹⁰

Explanation:

Based on the initial reaction:

N2O4 ⇄ 2NO2; K = 1.5x10³

Using Hess's law, we can multiply this reaction changing K:

3 times this reaction:

3N2O4 ⇄ 6NO2; K = (1.5x10³)³ =3.375x10⁹

The inverse reaction has a K of:

6NO2 ⇄ 3N2O4 K = 1/3.375x10⁹;

3 0

3 years ago

Suppose a 2.95 g of potassium iodide is dissolved in 350. mL of a 62.0 m M aqueous solution of silver nitrate. Calculate the fin

STALIN [3.7K]

Answer : The final molarity of iodide anion in the solution is 0.0508 M.

Explanation :

First we have to calculate the moles of $KI$ and $AgNO_3$ .

$\text{Moles of }KI=\frac{\text{Mass of }KI}{\text{Molar mass of }KI}$

Molar mass of KI = 166 g/mole

$\text{Moles of }KI=\frac{2.95g}{166g/mole}=0.0178mole$

and,

$\text{Moles of }AgNO_3=\text{Concentration of }AgNO_3\times \text{Volume of solution}=0.0620M\times 0.350L=0.0217mole$

Now we have to calculate the limiting and excess reagent.

The given chemical reaction is:

$KI+AgNO_3\rightarrow KNO_3+AgI$

From the balanced reaction we conclude that

As, 1 mole of KI react with 1 mole of $AgNO_3$

So, 0.0178 mole of KI react with 0.0178 mole of $AgNO_3$

From this we conclude that, $AgNO_3$ is an excess reagent because the given moles are greater than the required moles and KI is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of $AgI$