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dedylja [7]
3 years ago
15

A solution containing a nonvolatile solute will have

Chemistry
1 answer:
svetoff [14.1K]3 years ago
5 0
It is nonvolatile solute
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Adam observed properties of four different waves and
cupoosta [38]

Answer:

D)The sound quality for these waves cannot be compared.

Explanation:

I've done it on e2020

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3 years ago
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I NEED THE ANSWER QUICKKK!!!
julsineya [31]

Answer:  This is hard to do accurately, but here is my best assessment.

Explanation:

Experiment:  B  -  describes how the experiment was done

Conclusion:  A  -  The data support the prevailing hypothesis

Research:  D   -   This is what we analyzed

Analysis:  C  -  We compared the data

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2 years ago
A 7.0 g sample of a hydrocarbon (a molecule that has only hydrogen and carbon) is subject to combustion analysis. The mass of CO
Akimi4 [234]

Answer: The empirical formula for the given compound is CH_2

Explanation:

The chemical equation for the combustion of compound having carbon and hydrogen follows:

C_xH_y+O_2\rightarrow CO_2+H_2O

where, 'x' and 'y' are the subscripts of carbon and hydrogen respectively.

We are given:

Mass of CO_2=22.0g

We know that:

Molar mass of carbon dioxide = 44 g/mol

For calculating the mass of carbon:

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 22.0 g of carbon dioxide, \frac{12}{44}\times 22.0=6g of carbon will be contained.

For calculating the mass of hydrogen:

Mass of hydrogen = Mass of sample - Mass of carbon

Mass of hydrogen = 7.0 g - 6 g

Mass of hydrogen = 1.0 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{6g}{12g/mole}=0.5moles

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{1.0g}{1g/mole}=1.0moles

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.5 moles.

For Carbon = \frac{0.5}{0.5}=1

For Hydrogen  = \frac{1.0}{0.5}=2

Step 3: Taking the mole ratio as their subscripts.

The ratio of Fe : C : H = 1 : 2

Hence, the empirical formula for the given compound is C_{1}H_{2}=CH_2

4 0
3 years ago
How many grams of aluminum will<br> react fully with 1.25 moles Cl₂?
Liula [17]

2Al + 3Cl₂ → 2AlCl₃

mol Al = 2/3 x 1.25 = 0.83

mass Al = 0.83 x 27 g/mol = 22.41 g

3 0
2 years ago
Which of the following is equal to 1 mole?
nadya68 [22]
They are all equal to one mole (all of the above).
7 0
4 years ago
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