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Otrada [13]
3 years ago
14

In the equation for centripetal force, which expression represents the centripetal acceleration of the object? mv2 StartFraction

m over r EndFraction StartFraction v Superscript 2 Baseline over r EndFraction StartFraction m times v Superscript 2 Baseline over r EndFraction
Physics
2 answers:
Vinvika [58]3 years ago
8 0

Answer:

c

Explanation:

Sphinxa [80]3 years ago
3 0

Answer: \frac{V^{2}}{r}

Explanation:

According to Newton's 2nd Law of motion the force F is proportional to the mass Fm and acceleration a:

F=m.a (1)

On the other hand, the equation for the Centripetal force is:

F=\frac{mV^{2}}{r} (2)

Where:

V is the velocity

r is the radius of the circular motion

Making (1) and (2) equal:

m.a=\frac{mV^{2}}{r} (3)

Hence:

a=\frac{V^{2}}{r} This is the expression for the centripetal acceleration

It should be noted, this acceleration is directed toward the center of the circumference of the circular motion (that's why it's called centripetal acceleration).

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A ball is kicked on a planet the size of Earth but with twice the acceleration due to gravity. If the maximum height of the ball
USPshnik [31]

Answer:

The value t = 1.995 \  s

Explanation:

From the question we are told that

The acceleration due to gravity is a = 2g

The maximum height is h= 39 m

Generally from the kinematic equation

             s =  ut + \frac{1}{2} at^2

Here u  is the velocity of the ball at maximum height before it start falling and the value is  0 m/s

So

            39 =  0* t + \frac{1}{2} (2g)t^2

            39 = (9.8)t^2

            t =  \sqrt{3.9795918}

t = 1.995 \  s

3 0
4 years ago
Based on the Law of Conservation of Matter, what number should be placed in the box to balance the chemical equation below?
Rashid [163]

Answer:

2

Explanation:

Step 1: RxN

4Al + 3O₂ → Al₂O₃

Step 2: Balance RxN

We have 4 Al's and 6 O₂'s on the reactant side.

We need the same number of Al's and O₂'s on the product side.

4Al + 3O₂ → 2Al₂O₃

7 0
3 years ago
Read 2 more answers
580 nm light shines on a double slit with d=0.000125 m. What is the angle of the third dark interference minimum (m=3)?
Dmitry_Shevchenko [17]

Answer:

0.66 degrees

Explanation:

The computation of the angle of the third dark interference is shown below:

The condition of the minima is

Path difference = (2n +1) × \lambda÷ 2

For third minima, n = 2

Now

xd ÷ D = (2 × 2 + 1) × \lambda÷ 2

d tan Q_3 = 5\lambda ÷ 2

tan Q_3 = 5\lambda ÷ 2d

Q_3 = tan^-1 × (5\lambda ÷2d)

= tan^-1 × (5 × 580 × 10^-9) ÷ (2 × 0.000125)

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5 0
3 years ago
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Rus_ich [418]

Answer:

187.37 m

Explanation:

The wavelength of an electromagnetic wave is given by:

\lambda=\frac{c}{f}

where

c is the speed of light

f is the frequency

We see that the wavelength is inversely proportional to the frequency: this means that the shortest am wavelength will occur at the highest am frequency, which is

f=1600 kHz = 1600 \cdot 10^3 Hz

And substituting also the speed of light

c=2.99792 \cdot 10^8 m/s

We find the wavelength:

\lambda=\frac{2.99792 \cdot 10^8 m/s}{1600\cdot 10^3 Hz}=187.37 m

5 0
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mote1985 [20]

The area of the velocity time graph gives displacement of the body true or false?

The answer this is true.

8 0
3 years ago
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