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Sedbober [7]
3 years ago
3

Which is a longitudinal wave that requires a medium to move?

Physics
2 answers:
gladu [14]3 years ago
8 0
A.sound wave
It needs a medium
Nadya [2.5K]3 years ago
4 0

Answer:

A.sound wave

Explanation:

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The diagram shows a box in the periodic table. 15 P Phosphorus 31.0 What is the atomic number of the element shown? A. 46.0 B. 1
natali 33 [55]

Answer:

b 15

Explanation:

the atomic number is the number of the element

4 0
3 years ago
[K1 A2 T1 C1] A golfer strikes a golf ball on level ground.
gregori [183]

Answer:

Explanation:

See the file attached .

b ) Range of projectile

= u²sin2θ / g

= 42² sin32 x 2 / g

= 42² sin64 / 9.8

= 161.8 m

c )

Max height = u² sin²32 / 2 g

= 42² sin²32 / 2x 9.8

= 25.27  m .

6 0
3 years ago
Two parallel wires carry a current in the same direction. there is ___________ between the wires.
Arte-miy333 [17]
The correct answer is "an attractive force" between the wires.

Let's see why. Assume we have wire A on the left and wire B on the right, and that the current in both wires go upward.  First, let's find the direction of the magnetic field produced by wire A at wire B: by using the right-hand rule, we see that since the current (the thumb) goes upward, the magnetic field (given by the other fingers) at wire B is directed inside the paper.
Then we can apply again the right-hand rule to see what is the force on wire B. The index gives the direction of the current (upward), the middle finger the direction of the magnetic field (inside the paper), and the thumb gives the direction of the force: to the left, so toward wire A. This means the force is attractive. (you can re-do the procedure on wire A, and you will find the force on wire A is directed toward wire B)
7 0
3 years ago
A 5.0 g coin is placed 15 cm from the center of a turntable. The coin has static and kinetic coefficients of friction with the t
Alexandra [31]

Answer:

the coin does not slide off

Explanation:

mass (m) = 5 g = 0.005 kg

distance (r) = 15 cm = 0.15 m

static coefficient of friction (μs) = 0.8

kinetic coefficient of friction (μk) = 0.5

speed (f) = 60 rpm

acceleration due to gravity (g) = 9.8 m/s^{2}

lets first find the angular speed of the table

ω = 2πf

ω = 2 x π x 60 x \frac{1}{60}

ω  = 6.3 s^{-1]

Now lets find the maximum static force between the coin and the table so we can get the maximum velocity the coin can handle without sliding

static force (Fs) = ma

static force (Fs) = μs x Fn = μs x m x g

Fs = 0.8 x 0.005 x 9.8 = 0.0392 N

Fs = ma

0.0392 = 0.005 x a

a = 7.84 m/s^{2}

(Vmax)^{2} = a x r

(Vmax)^{2} = 7.84 x 0.15

Vmax = 1.08 m/s

ωmax = \frac{Vmax}{r}

ωmax = \frac{1.08}{0.15} = 7.2 s^{-1}

now that we have the maximum angular acceleration of the table, we can calculate its maximum speed in rpm

Fmax = \frac{ωmax}{2π}

Fmax = \frac{7.2}{2 x π} = 68.7 rpm

since the table is rotating at a speed less than the maximum speed that the static friction can hold coin on the table with, the coin would not slide off.

4 0
4 years ago
A light beam in glass (n = 1.5) reaches an air-glass interface, at an angle of 60 degrees from the surface. What is the angle of
tester [92]

Answer:

θ₂ = 35.26°

Explanation:

given,

refractive index of air, n₁ = 1

refractive index of glass, n₂ = 1.5

angle of incidence, θ₁ = 60°

angle of refracted light, θ₂ = ?

using Snell's Law

n₁ sin θ₁ = n₂ sin θ₂

1 x sin 60° = 1.5 sin θ₂

sin θ₂ = 0.577

θ₂ = sin⁻¹(0.577)

θ₂ = 35.26°

Hence, the refracted light is equal to  θ₂ = 35.26°

7 0
3 years ago
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