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nikitadnepr [17]
1 year ago
5

What does this image reveal about gravityon the moon compared to Earth?

Physics
1 answer:
elena-14-01-66 [18.8K]1 year ago
7 0

ANSWER:

The Moon's gravity is less than Earth's.

STEP-BY-STEP EXPLANATION:

When you jump, you fall back to the ground. Apples or leaves also fall: we are all attracted to the Earth. It is the terrestrial attraction due to the force of gravity.

The force of gravity also exists on the Moon. But since the Moon is smaller than the Earth, the attraction felt on the Moon is smaller than the Earth's attraction.

As the gravity is less, you can do things such as the one shown in the image.

As the force of attraction is less, the weight is less on the Moon, which can cause things that would be impossible on Earth.

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The frequency of a microwave signal is 9.76 ghz. what is its wavelength? (c = 3.00 × 108 m/s)
dolphi86 [110]
The basic relationship between frequency of an electromagnetic wave and wavelength of the wave is
c = \lambda f
where c=3 \cdot 10^8 m/s is the speed of light.

Manipulating the equation, we can rewrite it as
\lambda =  \frac{c}{f}

The frequency of the wave in our problem is
9.76 GHz = 9.76 \cdot 10^9 Hz
so if we use the previous formula, we find the correspondant wavelength:
\lambda =  \frac{3 \cdot 10^8 m/s}{9.76 \cdot 10^9 Hz} =0.031 m
8 0
3 years ago
A solid sphere of radius R is made of an insulating material. It holds a charge, Q, which is distributed evenly throughout the s
Vinvika [58]

Answer:

The magnitude of Electric Field is E=\dfrac{Qr}{4\pi \epsilon_0 R^3}

Explanation:

Given:

  • Radius of the solid sphere=R
  • Total charge of the sphere=Q

Let consider a Gaussian surface at a distance of r such that  0<r>R in the shape of sphere such that the electric Field due to this E and it is radially outwards.

The charge inside this Gaussian surface volume we have , q_{in}=\dfrac{Qr^3}{R^3}

Now using Gauss Law we have

E\times4\pi r^2=\dfrac{q_{in}}{\epsilon_0}\\E\times4\pi r^2=\dfrac{\dfrac{Qr^3}{R^3}}{\epsilon_0}\\E=\dfrac{Qr}{4\pi \epsilon_0 R^3}

5 0
3 years ago
A charged particle is accelerated in a uniform electric field. When its velocity is 2 m/s, its electric potential energy is 100
zavuch27 [327]

Answer:

particle's potential energy = 70J

Explanation:

From conservation of energy; K1 + Ue1 = K2 + Ue2

where K1 and K2 are the kinetic energies at two positions and Ue1 and Uue2 are the electrical potential energies at two positions.

k1 = 10J, Ue1 = 100J

K2 = 40J

substitute into K1 + Ue1 = K2 + Ue2

Ue2 = K1 + Ue1 - K2

= 10 +100 - 40

Ue2 = 70J

7 0
3 years ago
Small blocks A and B are held at rest on a smooth plane inclined at 30° to the horizontal. Each is held in equilibrium by a forc
Olin [163]
<h3><u>Answer</u> :</h3>

First of all, See the attachment for better understanding.

<u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u>

❂ <u>Weight of block A</u> :

➝ mg sin30° = 18

➝ W (1/2) = 18

➝ W = 18×2

➝ <u>W = 36N </u>

❂ <u>Weight of block B</u> :

➝ N sin30° = 18

➝ (Mg cos30°) sin30° = 18

➝ W' (√3/2)(1/2) = 18

➝ W' (√3/4) = 18

➝ W' = 72/√3

➝ <u>W' = 41.61N</u>

5 0
3 years ago
If the same change in velocity occurs in less time, does the magnitude of the corresponding average acceleration increase, decre
Zielflug [23.3K]

Answer:

increase

Explanation:

As acceleration is the time rate of change of velocity

a = Δv/t

with t in the denominator, smaller time values result in greater acceleration values with constant velocity change.

7 0
3 years ago
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