The basic relationship between frequency of an electromagnetic wave and wavelength of the wave is

where

is the speed of light.
Manipulating the equation, we can rewrite it as

The frequency of the wave in our problem is

so if we use the previous formula, we find the correspondant wavelength:
Answer:
The magnitude of Electric Field is 
Explanation:
Given:
- Radius of the solid sphere=R
- Total charge of the sphere=Q
Let consider a Gaussian surface at a distance of r such that 0<r>R in the shape of sphere such that the electric Field due to this E and it is radially outwards.
The charge inside this Gaussian surface volume we have , 
Now using Gauss Law we have

Answer:
particle's potential energy = 70J
Explanation:
From conservation of energy; K1 + Ue1 = K2 + Ue2
where K1 and K2 are the kinetic energies at two positions and Ue1 and Uue2 are the electrical potential energies at two positions.
k1 = 10J, Ue1 = 100J
K2 = 40J
substitute into K1 + Ue1 = K2 + Ue2
Ue2 = K1 + Ue1 - K2
= 10 +100 - 40
Ue2 = 70J
<h3><u>Answer</u> :</h3>
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❂ <u>Weight of block A</u> :
➝ mg sin30° = 18
➝ W (1/2) = 18
➝ W = 18×2
➝ <u>W = 36N </u>
❂ <u>Weight of block B</u> :
➝ N sin30° = 18
➝ (Mg cos30°) sin30° = 18
➝ W' (√3/2)(1/2) = 18
➝ W' (√3/4) = 18
➝ W' = 72/√3
➝ <u>W' = 41.61N</u>
Answer:
increase
Explanation:
As acceleration is the time rate of change of velocity
a = Δv/t
with t in the denominator, smaller time values result in greater acceleration values with constant velocity change.