Answer:
See explanation
Explanation:
For a reaction that proceeds by E1 mechanism, the rate determining step involves the formation of the carbocation.
The rate of formation of this carbocation depends only on the concentration of the t-butyl bromide since it is the only specie that enters into the rate equation.
Hence, when the concentration of t-butyl bromide is tripled, the rate of reaction is tripled.
Methanol does not enter into the rate equation hence doubling its concentration does not affect the rate of reaction.
Answer is: 315,29 grams of copper ore.
m(<span>chalcopyrite) = ?
</span>ω(CuFeS₂) = 55,0 % = 0,55.
<span>m(Cu) = 60,0 g.
mass percentage of copper in </span>CuFeS₂:
ω(Cu) = Ar(Cu) ÷ Mr(CuFeS₂).
ω(Cu) = 63,55 ÷ 183,4.
ω(Cu) = 0,346 = 34,6 %.
mass percentage of copper in chalcopyrite:
ω(Cu) : ω₁(Cu) = 100% : ω(CuFeS₂).
ω₁(Cu) = 19,03 % = 0,1903.
m(chalcopyrite) = 60,0 g ÷ 0,1903.
m(chalcopyrite) = 315,29 g.
Your answer would be 176.109.
Answer:
See below.
Explanation:
1. Real gases have significant volume.
2. Real gases have more complex interactions than ideal gases.
