Answer:
Mass = 18 g
Explanation:
Given data:
Number of molecules of Dicarbon hexahydride = 3.58 × 10²³ molecules
Mass of Dicarbon hexahydride = ?
Solution:
The given problem will solve by using Avogadro number.
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.
The number 6.022 × 10²³ is called Avogadro number.
For example,
3.58 × 10²³ molecules × 1 mol / 6.022 × 10²³ molecules
0.6 mol
Mass of Dicarbon hexahydride:
Mass = number of moles × molar mass
Mass = 0.6 mol × 30 g/mol
Mass = 18 g
Answer
B. acid + base --> salt + water
Explanation
Acids are substances that dissolve in water to produce hydrogen ions, H+.A base is a substance that dissolves in water to produce hydroxide ions, OH-.In a chemical reaction of an acid and a base, the products are a salt and water.For example when hydrocholoric acid is added to sodium hydroxide, a salt namely sodium chloride is formed with additional water.
Ionic bonding is a type of chemical bond in which valence electrons are lost from one atom and gained by another. This exchange results in a more stable, noble gas electronic configuration for both atoms involved. An ionic bond is based on attractive electrostatic forces between two ions of opposite charge.
<u>Answer:</u> This violates the law of constant composition.
<u>Explanation:</u>
Dalton's theory is based on mainly two laws, which are law of conservation of mass and law of constant composition.
Law of constant composition states that a compound always contain the elements in the fixed ratio by their masses.
For Example: In water
, the hydrogen and oxygen are present in the fixed ratio of 1 : 9 by their mass.
We are given:
A sample of titanium dioxide having 59.95 % of titanium and another sample of titanium dioxide having 60.10 % of titanium.
As, the compound is titanium dioxide. So, the mass percent of titanium must remain the same in both the elements.
Hence, this violates the law of constant composition.
Answer:
= 1.0593 g
Explanation:
1.1% NaCl by mass, means;
1.1 g per 100 g = 0.011
Therefore; the amount of NaCl present in 93.6 g of the solution is;
= 0.011 × 96.3 g
<u>= 1.0593 g</u>