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3 years ago

What can you conclude from the fact that electrons orbit far away from atomic nuclei?

1 answer:

5 0

Electrons are extremely small. Atoms are comprised mostly of empty space. Protons have a positive charge.
Hope this helps.

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N2(g) + 3H2(g) => 2NH3(g) Write the reaction again as a balanced reaction

Evgen [1.6K]

Answer:Consider the reaction N2(g) + 3H2(g) =; 2NH3(g). If hydrogen gas is added to this system at equilibrium, will the reaction shift towards reactants

8 0

2 years ago

I neeeddddd heeeellllllppppp I'll give you brainliest

aev [14]

not double replacement

it will be synthesis

they are fusing the two elements

plz mark brainliest

3 0

3 years ago

Phosphorus trichloride gas and chlorine gas react to form phosphorus pentachloride gas: PCl3(g)+Cl2(g)⇌PCl5(g). A 7.5-L gas vess

Tpy6a [65]

Answer:

The equilibrium constant in terms of concentration that is, $K_c=3.6243\times 10^{3}$ .

Explanation:

$PCl_3(g)+Cl_2(g)\rightleftharpoons PCl_5(g)$

The relation of $K_c\& K_p$ is given by:

$K_p=K_c(RT)^{\Delta n_g}$

$K_p$ = Equilibrium constant in terms of partial pressure.=98.1

$K_c$ = Equilibrium constant in terms of concentration =?

T = temperature at which the equilibrium reaction is taking place.

R = universal gas constant

$\Delta n_g$ = Difference between gaseous moles on product side and reactant side= $n_{g,p}-n_{g.r}=1-2=-1$

$98.1=K_c(RT)^{-1}$

$98.1 =\frac{K_c}{RT}$

$K_c=98.1\times 0.0821 L atm/mol K\times 450 K=3,624.30=3.6243\times 10^{3}$

The equilibrium constant in terms of concentration that is, $K_c=3.6243\times 10^{3}$ .

5 0

3 years ago

Read 2 more answers

When it’s summer in the northern hemisphere what Season is it in the Southern Hemisphere

Greeley [361]

Answer:

Winter

Explanation:

I dont know but whatev

4 0

2 years ago

Read 2 more answers

A 46.9 gram sample of a substance has a volume of about 3.5 centimeters3. It is solid at a room temperature of 23ºC. Out of the

Masteriza [31]

Answer:- C. Hafnium.

Solution:- Mass of the sample is 46.0 g and it's volume is $3.5cm^3$ .

From mass and volume, we can calculate it's density using the formula:

$density=\frac{mass}{volume}$

$density=\frac{46.9g}{3.5cm^3}$

$density=\frac{13.4g}{cm^3}$

On the basis of the density, this substance could either be mercury or hafnium. Since the substance is a solid at room temperature where as mercury is liquid. So, it can't be mercury.

The right choice is C) Hafnium.

3 0

3 years ago